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3 years ago

9

Which quantities in the advertisement represent a unit rate? 3 white shirts to 2 black shirts 2 black shirts for every 5 shirts

$10 per shirt $50 per shirt

2 answers:

Finger [1]3 years ago

7 0

Answer:

The Quantity 10$ per shirt represent a unit rate .

Step-by-step explanation:

Given:

There are 3 white shirts and 2 black shirts . per 10$ dollar.

To find:

Which quantities represent the unit rate ?

Solution:

Total of 5 shirts .

which means total of 50 dollar among 5 shirts.

i.e.50/5=10 dollars .

Hence each shirt causes 10 dollars or 10$ per shirt.

The Quantity 10$ per shirt represent a unit rate .

Paladinen [302]3 years ago

6 0

Answer:

10$ per shirt

Step-by-step explanation:

I got it correct on my quiz! <3

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Explain your answer!! <br><br> Will give brainlst

Novosadov [1.4K]

• So we know that.....

x represent bags of snack and y is bottles of water.

This equations shows the total amount and the cost of each water bottle and snack:

20.00 = 2.50x + 1.00y

Total: $20.00
Snack: $2.50
Water Bottle: $1.00

And this question shows the total items:

11 = x + y

Which there will be some snack + some water bottle = 11 items

—————————————————————

• Now I’m going to first solve for x, which is the amount of bags of snack.

I will use the equation, 11 = x + y.

(First, we’ll subtract y from both side, since we’re solving for x [UNDO])

11 = x + y
-y = - y
_______
11 - y = x —> so x is equal to 11 minus y.

—————————————————————

• Now we’re going to plug the 11 - y as x in the equation: 20.00 = 2.50x + 1.00y to solve for y.

20.00 = 2.50 (11 - y) + 1.00y

20.00 = 27.5 - 2.50y + 1.00y (Distributed)

20.00 = 27.5 - 1.50y (Combine like terms)

20.00 = 27.5 - 1.50y
-27.5 = -27.5 (Subtract -27.5 both side)
——————————
-7.5 = - 1.50y

-7.5 = -1.50y
—— ——— (Divide both side by -1.50)
- 1.50 = -1.50

5 = y

y is equals to 5, which means that there are 5 water bottles.

Now we know there are 11 items total and because there are 5 water bottles, there will be 6 bags of snacks. 11-5=6

—————————————————————

ANSWER:

They bought 6 bags of snacks! :)

4 0

3 years ago

What is the values of the soul out ion to the inequality<br> 9 < 3x + 4?

HACTEHA [7]

Answer:

x>5/3

Step-by-step explanation:

9<3x+4

3x+4>9

3x>9-4

3x>5

x>5/3

5 0

3 years ago

1/3 (6x - 9) + 3x - 8

Lena [83]

The answer is 5x-11

You have to distrivute 1/3 into 6x and -9 and after you have your answer for those you can combine like terms.

4 0

3 years ago

Evaluate the interval (Calculus 2)

Darya [45]

Answer:

$2 \tan (6x)+2 \sec (6x)+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x$

Multiply by the conjugate of 1 - sin(6x) :

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x$

$\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:$

$\implies \sin^2 (6x) + \cos^2 (6x)=1$

$\implies \cos^2 (6x)=1- \sin^2 (6x)$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

Expand:

$\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

$\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:$

$\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x$

$\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$

$\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}$

$\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}$

Simplify:

$\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}$

$\implies 2 \tan (6x)+2 \sec (6x)+\text{C}$

Learn more about indefinite integration here:

brainly.com/question/27805589

brainly.com/question/28155016

3 0

2 years ago

What is the area of the vertics 1,1 1,4 4,4 4,1

Annette [7]

Answer: 3x-x+2=4

Step-by-step explanation:

4 0

3 years ago