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Phoenix [80]
3 years ago
5

You deposit $400 into a savings account that earns 5% annual

Mathematics
1 answer:
Eva8 [605]3 years ago
3 0

Step-by-step explanation:

F=400(1+0.05/1)^1*t

After 1 year= $ 400.20

2= 400.40

3=$ 400.60

4= $ 400.80

5=$ 401.00

6= $ 401.20

7=$ 401.40

8=  $ 401.60

9=$ 401.80

10= $ 402.00

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What is the peremeter of this polygon? (With picture)
lyudmila [28]
Check the picture below.

so.. simply, use the distance formula, to get their length an add them up, and that's the perimeter of the polygon.


\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -1}}\quad ,&{{ 2}})\quad 
%  (c,d)
&({{ 2}}\quad ,&{{ 4}})\\
&({{ 2}}\quad ,&{{ 4}})\quad 
%  (c,d)
&({{ 3}}\quad ,&{{ -2}})\\
&({{ 3}}\quad ,&{{ -2}})\quad 
%  (c,d)
&({{ -2}}\quad ,&{{ -3}})\\
&({{ -2}}\quad ,&{{ -3}})\quad 
%  (c,d)
&({{ -1}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf -------------------------------\\\\
d=\sqrt{[2-(-1)]^2+(4-2)^2}\implies d=\sqrt{(2+1)^2+(2)^2}
\\\\\\
d=\sqrt{3^2+2^2}\implies \boxed{d=\sqrt{13}}\\\\
-------------------------------\\\\
d=\sqrt{(3-2)^2+(-2-4)^2}\implies d=\sqrt{1^2+(-6)^2}\implies \boxed{d=\sqrt{37}}\\\\
-------------------------------\\\\
d=\sqrt{(-2-3)^2+[-3-(-2)]^2}\implies d=\sqrt{(-5)^2+(-3+2)^2}
\\\\\\
d=\sqrt{(-5)^2+(-1)^2}\implies \boxed{d=\sqrt{26}}

\\\\
-------------------------------\\\\
d=\sqrt{[-1-(-2)]^2+[2-(-3)]^2}\implies d=\sqrt{(-1+2)^2+(2+3)^2}
\\\\\\
d=\sqrt{(1)^2+(5)^2}\implies \boxed{d=\sqrt{26}}

so, those are their lengths, sum them all up, that's the polygon's perimeter.

4 0
3 years ago
Which point is a solution to the system below 2y<-12x+4 y<-6x+4?
Lera25 [3.4K]

Answer: All points in the shaded region after 2y<-12x+4 is the solution.

Step-by-step explanation:

Since we have given that

2y

We need to find the point of solution to the system of inequalities:

Suppose

2y=-12x+4\\and\\y=-6x+4

We first check the consistency of the system of equation:

\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\\\\\frac{2}{1}=\frac{-12}{-6}=\frac{4}{4}\\\\2=2\neq 1

So, it is parallel system of equations, but we consider it as an inequality, so all the points in the shaded region is the solution.

Using zero test,

2y

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Similarly,

y

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So, the common part will be after 2y<-12x+4 .

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