Answer:
A' will be located 10 units from point A along ray PA
Step-by-step explanation:
we know that
The scale factor is equal to 3
To obtain PA', multiply PA by the scale factor
so
PA'=PA*3
PA=5 units
substitute
PA'=(5)*3=15 units
AA'=PA'-PA=15-5=10 units
therefore
A' will be located 10 units from point A along ray PA
Hi!
There might be different variations into how anyone would approach this problem but this is by far an easy way for me.
In order to solve fractional relationships with a variable, a perfect way to solve them would be to cross multiply and make them equal to each other.
You see the part '3y+12', and when you criss cross over to the other side of the equation, you get three. Multiply that together.
When you see the part '6', when you glide diagonally, you find '4y'. Multiply this together as well. Make them equal to each other.
(<em>This is how you do cross multiplication.)</em>
You should get something like this:
3(3y+12)=6(4y) Distribute the three on the left side and multiply. Do the same on the right.
9y+36=24y Now, you can combine like terms by subtracting 9y to the other side.
36=15y Isolate y and divide it by 15.
y=2.4
I was unclear of the answer, so I plugged in 2.4 into the original equation where the y variable was, and got the right answer, so 2.4 should be the correct one no matter how you got it.
I hope this helped!
Answer:
y=-3x-7
Step-by-step explanation:
y=mx+b , m represents slope, b represents y intercept
<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
