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borishaifa [10]
3 years ago
12

In how many ways can 7 distinct red balls and 5 distinct blue balls be placed in a row such that all red balls are adjacent,

Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0
The blue can be placed before the red or the red before the blue.
7 distinct balls have a permutation of 5040 while 5 distinct balls have a permutation of 120.
Each permutation of the reds can be combined with each permutation of the blues giving 5040×120=604800.
Double this to 1209600 to allow for the two positioning for red and blue.
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Find the length indicated. find CE
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Okay, to find length CE, your going to know the value of <em>x</em>. Length BC + CE = BD + DE.
3x+47+x+26=27+x+10
Simplify the equation to get
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you can choose one of four ways to continue, but I will choose to subtract x
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6 0
3 years ago
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
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