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aleksandr82 [10.1K]
3 years ago
8

Determine the domain and range of the following graph​

Mathematics
2 answers:
ipn [44]3 years ago
7 0

Answer:

<u>As per the graph we see:</u>

Domain is:

  • x = [0, 1]

Range is:

  • y = [-4, -3]

labwork [276]3 years ago
3 0
  • Domain=x axis co-ordinates
  • Range=y axis co-ordinates

Now

\\ \rm\Rrightarrow D_R=[0,1]

And

\\ \rm\Rrightarrow R_R=[-3,-4]

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Solve for brainliest!
balandron [24]

Answer:

$9.50

Step-by-step explanation:

8 0
3 years ago
What is the answer<br> Answer ASAP
vaieri [72.5K]

Step-by-step explanation:

-8.0-(-0.4+0.6)÷2

= -0.8-(0.2)÷2

= -0.8 -0.2 ÷2

= -0.9

use Bodmas method

7 0
3 years ago
Ava, Grace, Jayden, and Zoe together stacked a total of 50 brownies on a tray. Ava stacked 0.14 of the brownies, Grace stacked 4
OLEGan [10]

1. Zoe stacked the most brownies. She stacked 27 brownies out of the 50 brownies.

2. 15

3. 43 + 3n ≥ 70, so n ≥ 9

4. D. 58x + 13 + 58y

5. The answer would be ≤4

6. 9.94 + 10.01p ≤ 70, so p ≤ 6

7. C 40 89

8.  D. x+(x+5)=77

Hope I helped you! Please consider marking my answer the brainliest :)

4 0
3 years ago
Examine the fraction 3+2i4−2i. Which expression is the first step to simplify the fraction? 3+2i4−2i⋅3−2i3−2i
umka2103 [35]

Answer:

The correct answer is the last option.

Step-by-step explanation:

When you have a fraction with complex numbers, the first step to simplify is to multiply up and down the conjugate of the denominator, this will eliminate the complex part of the denominator, and in this way you can separate the expression in its real and complex part.

For the expression:

\frac{3 + 2i}{4-2i&#10;}

The denominator conjugate is 4 + 2i

When multiplied, the denominator is:

4 ^ 2 -4i ^ 2 = 16 -4 (-1) = 20

4 0
3 years ago
Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated
koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.


With this, you will need to use the distance formula, \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, on XY, YZ, and ZX.



XY: \sqrt{(3-1)^2+(1-6)^2}


Firstly, solve inside the parentheses: \sqrt{(2)^2+(-5)^2}


Next, solve the exponents: \sqrt{4+25}


Next, solve the addition, and XY's distance will be √29



(The process is the same with the other 2 sides, so I'll go through them real quickly)


YZ:

\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}



ZX:

\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}



Now that we got the 3 sides, we can add them up: \sqrt{29}+\sqrt{13} +\sqrt{34} =14.8


In short, your answer is 14.8, or the second option.

8 0
3 years ago
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