Another way to write this is:
x = 23y + 5
xy = 6732
Now plug in the first equation into the second:
(23y + 5)y = 6732
23y^2 + 5y - 6732 = 0
Either use quadratic equation or factor:
(y - 17)(23y + 396) = 0
y = 17 or -396/23
You know you can automatically eliminate the second y because it's negative and you need the two integers to multiply to a positive number (6732).
Plug y = 17 back into either equation (second might be easier):
17x = 6732
x = 396
<span>Hello there.
What is the equation for x+1, x+2, x+3
</span><span>4x</span>+<span>3</span>
Answer:
<h3>y= log³ x</h3>
<h3>The logarithmic function y = logax is defined to be equivalent to the exponential equation x = ay. y = logax only under the following conditions: x = ay, a > 0, and a≠1. It is called the logarithmic function with base a.</h3>
Step-by-step explanation:
<h3>i hope it helps</h3><h3># i love to Taylor spears</h3>
