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aleksandr82 [10.1K]
3 years ago
8

Determine the domain and range of the following graph​

Mathematics
2 answers:
ipn [44]3 years ago
7 0

Answer:

<u>As per the graph we see:</u>

Domain is:

  • x = [0, 1]

Range is:

  • y = [-4, -3]

labwork [276]3 years ago
3 0
  • Domain=x axis co-ordinates
  • Range=y axis co-ordinates

Now

\\ \rm\Rrightarrow D_R=[0,1]

And

\\ \rm\Rrightarrow R_R=[-3,-4]

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Find the slope and y-intercept from the following graph of a linear equation.
Alexxx [7]

Answer:

The slope is 4 and y-intercept is actually 3... (I hope)

Remember rise over run, here you can see that it goes up 4 and over 1.

I am so sorry, I'm not good at explaining

4 0
2 years ago
guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

brainly.com/question/12426369

#SPJ4

3 0
1 year ago
Si: P(x+2) = 2(x+2)^3 + x^2 +4x +4<br> Calcular : P(-4)
Tom [10]

Answer:

Step-by-step explanation:

6 0
3 years ago
Erin gets her exercise by running. The graph shows the distances she covers in a given amount of time. How many hours does it ta
soldi70 [24.7K]

The correct answer is  c. 2 \frac{1}{2} hours

Explanation:

The graphic shows the relationship between the distance Erin covers by running and the time this requires. Additionally, to know the specific time that takes for Erin to run a specific distance or vice versa it is necessary to observe at which point the two variables intersect in the line of the graph.

According to this, Erin runs 25 miles (y-axis) in 2.5 hours (x-axis), which you can know because in the line shown by the graph the distance 25 miles that is in the middle of 20 and 30 miles intersects with 2.5 hours or the middle between 2 and 3. Additionally, this number can be expressed as 2 and a half hours, 2.5 or even 2 \frac{1}{2} hours because the fraction represents half. This makes option C the answer.

6 0
4 years ago
H(t) = 4t+20 What is h(_____)=4?
kaheart [24]

Answer:  h(-4)  

Step-by-step explanation:

If h(x) something is equal to 4  then set the equation equal 4  and solve for t.

4t +20 = 4

    -20    -20  

4t = -16

t = -4  

So h(-4) = 4

7 0
4 years ago
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