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3 years ago

HELP!!! PLEASE!!

Mathematics

2 answers:

kvv77 [185]3 years ago

7 0

Answer:

(-9,15)

Step-by-step explanation:

v-u = ((-4-5),(7-(-8)))

= (-9,(7+8))

= (-9,15)

Free_Kalibri [48]3 years ago

3 0

Answer:

(9,-15)

Step-by-step explanation:

( 5 - (-4), -8 -7 )

( 9 , -15)

I hope my answer helps you.

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3 years ago

A right △ABC is inscribed in circle k(O, r). Find the radius of this circle if:

natta225 [31]

We have been given that a right △ABC is inscribed in circle k(O, r).

m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.

First of all, we will draw a diagram that represent the given scenario.

We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.

We will use sine to find side AB.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(30^{\circ})=\frac{AC}{AB}$

$\text{sin}(30^{\circ})=\frac{18}{AB}$

$AB=\frac{18}{\text{sin}(30^{\circ})}$

$AB=\frac{18}{0.5}$

$AB=36$

Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is $\frac{36}{2}=18$ .

Therefore, the radius of given circle would be 18 cm.

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4 years ago

What is the approximate value of 31 square root? MAFS.8.NS.1.2<br> 5<br> 6<br> 15<br> 16

PtichkaEL [24]

Answer:

Step-by-step explanation:

$\sqrt{31} =5.56$

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4 0

3 years ago

Read 2 more answers

Find the horizontal asymptote off of x equals quantity 3 x squared plus 3x plus 6 end quantity over quantity x squared plus 1.

vaieri [72.5K]

Answer:

y = 3

Step-by-step explanation:

y = (3x² + 3x + 6) / (x² + 1)

The power of the numerator and denominator are equal, so as x approaches infinity, y approaches the ratio of the leading coefficients.

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4 years ago

A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr

Goryan [66]

Answer:

Generally the barrier width is $a = 1.9322 *10^{-9} \ m$

Step-by-step explanation:

From the question we are told that

The tunneling probability required is $T = 1 * 10^{-5}$

The barrier height is $V_o = 0.4 eV$

The electron energy is $E = 0.08eV$

Generally the wave number is mathematically represented as

$k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }$

Here m is the mass of the electron with the value $m = 9.11 *10^{-31} \ kg$

h is is know as h-bar and the value is $\= h = 1.054*10^{-34} \ J \cdot s$

$k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }$

=> $k = 3.073582 *10^{9} \ m^{-1}$

Generally the tunneling probability is mathematically represented as

$T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}$

$1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}$

=> $6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}$

Taking natural log of both sides

$ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}$

=> $-11.8776 = -2 * 3.0736 *10^{9} * a}$

=> $a = 1.9322 *10^{-9} \ m$

4 0

3 years ago