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Fiesta28 [93]
3 years ago
10

PLEASE HELP!! thanks :)

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

This is my graph...

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Step-by-step explanation:

Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value x_{0} such that P(X < x_{0}) = 0.76, but, 0.76 = P(X < x_{0}) = P((X-63.6)/2.5 < (x_{0}-63.6)/2.5) = P(Z < (x_{0}-63.6)/2.5), i.e., (x_{0}-63.6)/2.5 is the 76th percentile of the standard normal distribution. So, (x_{0}-63.6)/2.5 = 0.7063, x_{0} =63.6+(2.5)(0.7063) = 65.3658. Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.

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A restaurant uses one-third of their stock of cooking oil in a week. If 20 gallons are left, how
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Step-by-step explanation:

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NEED HELP WITH THIS QUESTION ASAP
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What is 20 / 65.9635
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the answer to your question is 0.3031979807

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