Answer:
Choice D is correct answer.
Step-by-step explanation:
Two equations are given:
3x-4y=28 eq(1)
4x+10y=20 eq(2)
y=mx+c is slope-intercept form of line where m is slope and c is y-intercept.
We have to make given equations in the form of slope-intercept.
eq(1) is:
3x-4y=28
Adding -3x to both sides of above equation,we get
-3x+3x-4y=-3x+28
0-4y=-3x+28
-4y=-3x+28
Multiplying by -1/4 to both sides of above equation,we get
-1/4(-4y)=-1/4(-3x+28)
y=-1/4(-3x)-1/4(28)
y=3/4x-7 is slope intercept form of eq(1) where m=3/4 and c=-7.
eq(2) is:
4x+10y=20
Adding -4x to both sides of above equation,we get
-4x+4x+10y=-4x+20
0+10y=-4x+20
10y=-4x+20
Multiplying by 1/10 to both sides of above equations ,we get:
1/10(10y)=1/10(-4x+20)
y=1/10(-4x)+1/10(20)
y=-2/5x+2 is slope-intercept form of eq(2) where m=-2/5 and c=2.
As we observed both of the lines have different slopes,so they have one solution.
hence,they are intersecting lines.
