2 years ago

Simplify. (-2)^-3 ?????

1 answer:

3 0

Remember
$(ab)^c=(a^c)(b^c)$ and
$x^{-m}= \frac{1}{x^m}$
so
$(-2)^{-3}= \frac{1}{(-2)^3}= \frac{1}{(-1)^3(2)^3}=\frac{1}{(-1)(8)}=\frac{1}{-8}=\frac{-1}{8}$

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