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3 years ago

Simplify. (-2)^-3 ?????

1 answer:

3 0

Remember
$(ab)^c=(a^c)(b^c)$ and
$x^{-m}= \frac{1}{x^m}$
so
$(-2)^{-3}= \frac{1}{(-2)^3}= \frac{1}{(-1)^3(2)^3}=\frac{1}{(-1)(8)}=\frac{1}{-8}=\frac{-1}{8}$

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Sin0=20/29 find tan 0

Ket [755]

Answer:

Step-by-step explanation:

here opposite =20, hypotenuse=29

to find adjacent use formula

a^2+b^2=c^2

20^2+b^2=29^2

400+b^2=841

b^2=841-400

b= $\sqrt{441\\}$

b=21

tan theta=opposite/adjacent

=20/21

therefore tan theta =20/21

6 0

3 years ago

Read 2 more answers

If x + y = 4 and x2 − y2 = 64, what is the value of (x − y)?

murzikaleks [220]

The value of (x-y) is 16

Further explanation:

We have to use the given values to find the value

Given

$x+y=4\\and\\x^2-y^2=64$

We will use:

$x^2-y^2=64$

Simplifying by using: $x^2-y^2=(x+y)(x-y)$

So,

$(x+y)(x-y)=64$

As we know that x+y=4

Putting the value in equation

$(4)(x-y)=64$

Dividing both sides by 4

$\frac{4(x-y)}{4}=\frac{64}{4}\\x-y=16$

The value of (x-y) is 16

Keywords: Algebraic formulas, Simplification

Learn more about algebraic expressions at:

#LearnwithBrainly

7 0

3 years ago

Factor Completely<br><br> -m^3-2m^2-16m-32

klio [65]

Answer:

-(m+2)(m^2+16)

Step-by-step explanation:

6 0

2 years ago

A right square pyramid has a slant height of 10 feet, and the length of a side

kotykmax [81]

Step-by-step explanation:

take the base square. find the diagonal

16^2+16^2 = 2*16^2= d^2

d= 16√2

half of the diagonal will form the baSe of right triangle of hypotenuse 10. but the base will be 8√2 which is greater than 10. so I feel the slant hr has to be different and more than 10

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2 years ago

Did you hear the one about the acupuncture

Alecsey [184]

The answer is "It was A Jab Well Done" You have to finish the whole sheet to get the answer

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3 years ago