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NNADVOKAT [17]
3 years ago
10

Simplify. (-2)^-3 ?????

Mathematics
1 answer:
Licemer1 [7]3 years ago
3 0
Remember
(ab)^c=(a^c)(b^c) and
x^{-m}= \frac{1}{x^m}
so
(-2)^{-3}= \frac{1}{(-2)^3}= \frac{1}{(-1)^3(2)^3}=\frac{1}{(-1)(8)}=\frac{1}{-8}=\frac{-1}{8}
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8 0
4 years ago
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where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

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4 years ago
57% people ordered steak. 120 did not. how many customers were there that night?
jok3333 [9.3K]
X - number of customers

120+57\%x=x\\
120+0.57x=x\\
0.43x=120\\
x\approx297.07

There can't be a fraction of the number of people, so there must be some mistake in the question.
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4 0
3 years ago
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