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Kaylis [27]
3 years ago
14

What is 4/3 as a fraction.

Mathematics
1 answer:
motikmotik3 years ago
8 0

4/3 as a fraction is 1 1/3. The volume of a circle is not a thing, so I am going to assume your asking volume of the balloon.

9 = radius

The volume is of the balloon is 4/3 x 9 x 9 x 9 x 3.14 (pi)

Volume =  3052.08 cubic inches

If you are asking for area of circle

Area of Circle =  9 x 9 x 3.14

Area = 254.34 sq. inches

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Which point is on the line y = -2x + 3?<br><br> (-2, -1)<br> (3, 3)<br> (3, -3)<br> (-3, -9)
xenn [34]
I think the answer is (3,3)

5 0
3 years ago
Please help :) Is the relationship shown by the data linear? If so model the data with an equation.
MrRissso [65]

Answer:

y-5=5/4(x-1)

Step-by-step explanation:

the slope is 1.25

m=y2-y1/x2-x1=10-5/5-1=5/4=1.25

y-5=(5)/(4)(x-1)=

y=(5)/(4)x+(15)/(4) this one is linear

it is a linear function and the

5 0
3 years ago
A consulting firm has received 2 Super Bowl playoff tickets from one of its clients. To be fair, the firm is randomly selecting
Soloha48 [4]

Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

There employees are 6 secretaries, 5 consultants and 4 partners in the firm.

a.) The probability that a secretary wins in the first draw

= \frac{number \hspace{0.1cm} of \hspace{0.1cm} secreataries}{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} employees}  = \frac{6}{15}

b.) The probability that a secretary wins a ticket on second draw.  It has been given that a ticket was won on the first draw by a consultant.

p(secretary wins on second draw | consultant  wins on first draw)

=\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}

= \frac{\frac{5}{15}  \times \frac{6}{14}}{\frac{5}{15} }  = \frac{6}{14}  .

The probability that  a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw  = \frac{6}{15} is not true.

The probability that a secretary wins on the second draw  = \frac{number \hspace{0.1cm} of  \hspace{0.1cm} secretaries  \hspace{0.1cm} remaining } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} remaining}  = \frac{6 - 1}{15 - 1}  = \frac{5}{14}

c.) The probability that a consultant wins on the first draw  =

\frac{number \hspace{0.1cm} of  \hspace{0.1cm} consultants  \hspace{0.1cm}  } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} }  = \frac{5 }{15}  = \frac{1}{3}

d.) The probability of two secretaries winning both tickets

= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)

= \frac{6}{15}  \times \frac{5}{14}  = \frac{1}{7}

Therefore the only statement that is not true is b.)

5 0
3 years ago
The Odd and even numbered hotel rooms are on different sides of the hall room 23q is between which two rooms
diamong [38]
It is between room 21 and 25
6 0
3 years ago
How do i do this plz help
e-lub [12.9K]

Answer:

its 60 bc 6-2÷180

4÷180=45

8 0
3 years ago
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