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3 years ago

Please help me with this question

Mathematics

1 answer:

Trava [24]3 years ago

4 0

Applying the formula for the area of a sector and length of an arc, the value of k is calculated as: 27.

<h3>What is the Area of a Sector?</h3>

Area of a sector of a circle = ∅/360 × πr²

<h3>What is the Length of an Arc?</h3>

Length of arc = ∅/360 × 2πr

Given the following:

Radius (r) = 9 cm
Length of arc = 6π cm
Area of sector = kπ cm²

Find ∅ of the sector using the formula for length of acr:

∅/360 × 2πr = 6π

Plug in the value of r

∅/360 × 2π(9) = 6π

∅/360 × 18π = 6π

Divide both sides by 18π

∅/360 = 6π/18π

∅/360 = 1/3

Multiply both sides by 360

∅ = 1/3 × 360

∅ = 120°

Find the area of the sector:

Area = ∅/360 × πr² = 120/360 × π(9²)

Area = 1/3 × π81

Area = 27π

Therefore, the value of k is 27.

Learn more about area of sector on:

brainly.com/question/22972014

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4 years ago

Jaylen and ken started jogging from the same place in the opposite directions along a straight path. jaylen's speed was 30 m/min

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The average speed of Ken is 70 m/min. Using the relation between the speed and distance, the required speed for Ken is calculated.

<h3>What is the relation between speed and distance?</h3>

The relationship between speed S and distance D with a period T is formed as

S = D/T

Units: m/sec (basic unit)

<h3>Calculation:</h3>

Given that,

Jaylen and Ken started jogging from the same place in opposite directions along a straight path.

This means, that the sum of distances traveled by both of them in opposite directions = 13.6 km (since it is given that at the end of their jogging, they are 13.6 km apart)

Consider,

The distance traveled by Jaylen = x km

Then the distance traveled by Ken = x - 2.4 km (since Jaylen jogged 2.4 km more than Ken)

Step 1: Finding the distance traveled by them:

x + x - 2.4 = 13.6

⇒ 2x = 13.6 + 2.4

⇒ 2x = 16

⇒ x = 8 km

So, the distance travelled by Jaylen = 8 km and by Ken = 8 - 2.4 = 5.6 km

Step 2: Finding the average speed traveled by Ken:

Since it is given that,

Jaylen's speed was 30 m/min faster than Ken's speed.

So,

For 30 m, the time = 1 min

then for 2.4 km i.e., 2400 m, the time = 80 min.

Therefore,

the average speed of Ken S = D/t

⇒ S = 5600 m / 80 min

∴ S = 70 m/min.

So, the average speed of Jaylen will be 70 m/min + 30 m/min = 100 m/min.

Thus, the average speed of Ken is 70 m/min.

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5 0

2 years ago

Please help me with this question​

Please help me with this question