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klemol [59]
2 years ago
10

50 POINTS PLS ANSWER QUICK!!

Mathematics
2 answers:
Andre45 [30]2 years ago
8 0

\qquad\qquad\huge\underline{{\sf Answer}}

Linear equation has a degree of 1, that means the maximum power of a variable in a linear equation/expression should be 1. if an equation doesn't satisfy this condition then it's not a linear equation.

So, by Observing the choices, we get to the conclusion that the one which isn't a linear equation is B

\qquad \sf  \dashrightarrow \: {x}^{3}  - 5 {y}^{2}  = 4

Here, the variables have greater powers tham one, and degree is 3. so it's the required Answer ~

fomenos2 years ago
3 0

Answer:

I think that B is not a linear equation.

Step-by-step explanation:

Linear eqautions can not contain exponents in them. B has x to the power of 3 and y to the power of 2, ruling it out to be a linear equation.
I hope this helps! :)

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4 bags of cement do 18m(squared), how many m(squared) can be done with 7 bags ?
Elis [28]
I think 7 bags do 31.5 m squared
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3 years ago
1) Solve the inequality.<br> 8x + 9 &lt; 4x - 3
Nitella [24]

Answer:

x < -3

Step-by-step explanation:

subtract 4x: 4x + 9 < -3

subtract 9: 4x < -12

divide by 4: x < -3

3 0
3 years ago
Please can you give me the answers to the questions above in standard form.​
ivanzaharov [21]

Answer:

a) 4.5 \times 10^{11}

b) 3.5 \times 10^{3}

Step-by-step explanation:

a) We have to simplify the below expression in standard form.

The expression is (5\times 10^{3}) \times (9 \times 10^{7})

Now, (5\times 10^{3}) \times (9 \times 10^{7})

= (9 \times 5) \times (10^{3} \times 10^{7})

= 45 \times 10^{(3 + 7)} {Since a^{b} \times a^{c} = a^{(b + c)}}

= 45 \times 10^{10}

= 4.5 \times 10^{11} (Answer)

b)  We have to simplify the below expression in standard form.

The expression is (7\times 10^{5}) \div (2 \times 10^{2})

Now, (7\times 10^{5}) \div (2 \times 10^{2})

= (7 \div 2) \times (10^{5} \div 10^{2})

= 3.5 \times 10^{(5 - 2)} {Since a^{b}\div a^{c} = a^{(b - c)}}

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3 0
3 years ago
Which two numbers add up to 6 and multiply to -40
Damm [24]
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3 0
3 years ago
Ursula and Velda live 4 km apart. They leave their homes at the same time, walking towards each other. If Ursula walks at a rate
vladimir2022 [97]

Answer: 250 m

Step-by-step explanation:

Given

Distance between Ursula and Velda house is 4 km or 4000 m

Ursula walks at the rate of 400\ m/h\ or\ \frac{20}{3}\ m/min

Velda walks at the rate of 600\ m/h\ or\ 10\ m/min

Time taken by them to cover 4000 m is

\Rightarrow \dfrac{4000}{400+600}=4\ h\ or\ 240\ min

Distance covered by them 15 min before they meet

Ursula =\frac{20}{3}\times 225=1500\ m

Velda =10\times 225=2250\ m

The total length covered by them is =1500+2250=3750\ m

They are 4000-3750=250\ m apart before they meet

6 0
2 years ago
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