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Goshia [24]
3 years ago
5

The number of cows on a farm increased by 60. Because of better food, the amount of milk from each cow went up from 12.8 liters

per day to 15 liters per day on the average. How many cows are on the farm now if the farmer gets 1340 liters of milk more per day?
Mathematics
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

Step-by-step explanation:

Number of cows increased=60

Old quality of milk consumed=12.8litres

New Increase in milk consumed=15litres

Therefore the number of cows in the farm if the quality of milk is 1340litres=y

Therefore, 1cow =15litres

y cows= 1340litres

Crossmultiply:

15litres×ycows=1340litres

Make y the subject of formula

y= 1340÷15

y=89.33cows

Therefore,the number of cows on the farm if farmer gets 1340litres of milk would be 89cows.

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Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
Need some help asap​
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Answer:

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Step-by-step explanation:

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Use the diagram to answer the question
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