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Shalnov [3]
2 years ago
6

What makes a recipe for a meal an example of an algorithm?

Computers and Technology
1 answer:
LuckyWell [14K]2 years ago
6 0

Answer:

B

Explanation:

Got it right on edge 2022

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Pleas help I will give brainiest
stellarik [79]
1) A
2)D
3)C
4)A
5)D
Hope this will help u
5 0
3 years ago
Read 2 more answers
Given the list of customer segments below please create a new list of the names of the segments only using(a) a for loop(b) a li
Alchen [17]

Answer:

new_segment = [ ]

for segment in segments:

   new_segment.append({'name': segment, 'average_spend': money})

print( new_segment)

Using list comprehension:

new_segment =[{'name': segment, 'average_spend': money}  for segment in segments]

Using map():

def listing(a):

   contain =  {'name': segment, 'average_spend': money}

   return contain

new_segment = [ ]

new_segment.append(map( listing, segment))

print(list(new_segment)

Explanation:

The python codes above create a list of dictionaries in all instances using for loop, for loop in list comprehension and the map function which collect two arguments .

7 0
3 years ago
Using MARS/MIPS
slega [8]

Answer:

Explanation:

MIPS program which increments from 0 to 15 and display results in Decimal on the console

In this program the user defined procedures print_int and print_eot were used to print the integer values and new line characters(\n) respectively.the mechanisam of the loop is explaine in the comment section of the program.

     addi $s0, $0, 0

     addi $s1, $0, 15

print_int:

              li $v0, 1                # system call to print integer

              syscall                

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s1<$s0

beq $s0, $0, end

end:

MIPS progam to increment from 0 to 15 and display results in Hexadecimal on the console

this program is slightly differed from the previous program in this program the system call issued in print_int is implemented with a system call that prints numbers in hex.

addi $s0, $0, 15

     addi $s1, $0, 0

print_int:

   li      $v0,34                  # syscall number for "print hex"

   syscall                         # issue the syscall

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s0>$s1

beq $s0, $0, end

end:

5 0
3 years ago
A computer program is tested by 5 independent tests. If there is an error, these tests will discover it with probabilities 0.1,
Svetllana [295]

Answer:

0.8488

Explanation:

Let E =error found by test 1

Let F=error found by test 2

Let G=error found by test 3

Let H=error found by test 4

Let I= error found by test 5

Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5

therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5

Tests are independent P(not E & not F &not G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512

P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488

5 0
3 years ago
The Accounting department is testing a new payroll system server. To facilitate their tests, they would like to add the server t
natka813 [3]

i am still 13  

udduudncd nd ndcdnnbdmbfvmd

4 0
3 years ago
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