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Kobotan [32]
3 years ago
8

.Although SQL is a language, you don’t use it to write applications? (true, false)

Computers and Technology
1 answer:
Olin [163]3 years ago
3 0

Answer:

The correct answer for the given question is true .

Explanation:

SQL is an Structural query language that is used for accessing the database basically it is an query language which is used for communicating with database by executed the query .

The following are the function of SQL  

SQL can insert the data into database

it can update the record into database

SQL can retrived the database.

We do not use SQL for writing application it is only used to accessing the database  

For create application we can use programming language Like PHP,ASP,JAVA ,PYTHON.etc.

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Write a program called DeliveryCharges for the package delivery service. The program should use an array that holds the 10 zip c
Vlad [161]

Answer:

import java.util.Scanner;

public class DeliveryCharges

{

public static void main(String[] args) {

 

       String[] zips = {"01234", "11234", "21234", "31234", "41234", "51234", "61234", "71234", "81234", "91234"};

    double[] prices = {2.2, 1.0, 3.6, 6, 9, 7.1, 0.8, 4.7, 3.3, 5.2};

    int index = -1;

    Scanner ob = new Scanner(System.in);

    System.out.print("Enter the zip code for your delivery: ");

    String zip = ob.next();

   

    for (int i=0; i<10; i++) {

        if (zip.equals(zips[i])) {

            index = i;

        }

    }

       

    if (index!= -1)

       System.out.println("Delivery charge to " + zips[index] + " is: " + prices[index]);

    else

       System.out.println("No delivery to " + zip);

}

}

Explanation:

Initialize the zips and prices

Initialize index that represents the index of the zip code. If the entered zip code is in the array

Ask the user to enter the zip code

Create a for loop that iterates through the zips. If the entered zip is in the zips, set its index to index

When the loop is done, check if the index. If the index is not -1, that means zip code was found in the zips array, print the corresponding price from the price array. Otherwise, print no delivery for the entered zip code

8 0
4 years ago
Why are iterators useful?
Marina CMI [18]
It is d because I said it is
6 0
3 years ago
If you want smaller tables to fit on a single page?
Vinil7 [7]
Well what i do is i make every thing a little smaller and if that dose not work make it bigger so that it just gos over the bottom of the page
8 0
3 years ago
Today we will be making a Caesar Cipher to encrypt and decrypt messages.A Caesar Cipher is a simple cipher that translates one l
Len [333]

Answer:

#include <iostream>

#include <stdio.h>

#include <ctype.h>

using namespace std;

string

encrypt (string text, int s)

{  string resultingString = "";

 for (int i = 0; i < text.length (); i++)

   {      if (!isspace (text[i]))

{

  if (isupper (text[i]))

    resultingString += char (int (text[i] + s - 65) % 26 + 65);

  else

  resultingString += char (int (text[i] + s - 97) % 26 + 97);

}

     else

{

  resultingString += " ";

}

  }

 return resultingString;

}

string

decrypt (string text, int s)

{

 string resultingString = "";

 for (int i = 0; i < text.length (); i++)

   {

     if (!isspace (text[i]))

{

  if (isupper (text[i]))

    resultingString += char (int (text[i] + s - 65) % 26 + 65);

  else

  resultingString += char (int (text[i] + s - 97) % 26 + 97);

}

     else

{

  resultingString += " ";

}

   }

 return resultingString;

}

string upper(string str){

   for (int i=0;i<str.length();i++){

       str[i]=toupper(str[i]);

   }

   return str;

}

int

main ()

{

 string text = "This is test text string";

 

 int s = 3;

 string cipherText = "";

 string decipherText = "";

int menu=-1;

while (menu!=3){

   cout<<"1. Encrypt"<<endl;

   cout<<"2. Decrypt"<<endl;

   cout<<"3. Exit"<<endl;

   cin >>menu;

   cin.ignore();

   if(menu==1){

       cout<<"Enter Plain string "<<endl;

       getline(cin,text);

       text=upper(text);

         cipherText = encrypt (text, s);

           cout << "cipher text: " << cipherText << endl;

   }

   else if(menu==2){

       cout<<"Enter Encrypted string "<<endl;

       getline(cin,cipherText);

               cipherText=upper(cipherText);

         decipherText = decrypt (cipherText, 26 - s);

 cout << "decipher text: " << decipherText << endl;

   }

   else {

       cout<<"Not valid"<<endl;

   }

}

 return 0;

}

Explanation:

Display menu with options 1 encrypt, 2 decrypt, 3 exit. Write a function to translate string to upper case. Iterate through string and for each index use toupper function to translate alphabet to upper case and store it back to current index of string.On exiting from loop return string. Pass upper case string to encrypt function.

In encrypt function pass string by reference and shift value. Create an empty string resultingString. Iterate through string for each character check if its space, if its a space add it to resulting string otherwise using ascii values convert char to its ascii add shift value and subtract 65 (staring ascii value for capital alphabet) take modules with 26 for new character and than add 65 to get alphabet.Now add this alphabet to resulting string. Upon loop completion return resultingString.

For decryption use same function as encryption. We are using cyclic property to decrypt using same function therefor subtract shift from 26 and pass resulting shift value to decrypt function.

8 0
3 years ago
python Assume letters A, E, I, O, and U as the vowels. Write a program that prompts the user to enter a string and displays the
Roman55 [17]

Answer:

vowels = 0

consonants = 0

string = input("Enter string: ")

for x in string:

   if x.isalpha():

       if x in "AEIOU":

           vowels += 1

       else:

           consonants += 1

print("Vowels =",vowels)

print("Consonants =",consonants)

Explanation:

8 0
3 years ago
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