For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
As given in the question,
Given function is equal to :
f(t) = 2t + 1
Simplify the given function using definition of Laplace transform we have,
L(f(t))s = 
= ![\int\limits^\infty_0[2t +1] e^{-st} dt](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cinfty_0%5B2t%20%2B1%5D%20e%5E%7B-st%7D%20dt)
= 
= 2 L(t) + L(1)
L(1) = 
= (-1/s) ( 0 -1 )
= 1/s , ( s > 0)
2L ( t ) = 
= ![2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]](https://tex.z-dn.net/?f=2%5Bt%5Cint%5Climits%5E%5Cinfty_0%20e%5E%7B-st%7D%20-%20%5Cint%5Climits%5E%5Cinfty_0%20%28%7B%28d%2Fdt%29%28t%29%20%5Cint%5Climits%5E%5Cinfty_0e%5E%7B-st%7D%20%5C%2C%20dt%20%29dt%5D)
= 2/ s²
Now ,
L(f(t))s = 2 L(t) + L(1)
= 2/ s² + 1/s
Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
Learn more about Laplace transform here
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E^2=0.36 take the square root of both sides
e=±0.6
<span>Simplifying
3x + 6 = 2x
Reorder the terms:
6 + 3x = 2x
Solving
6 + 3x = 2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2x' to each side of the equation.
6 + 3x + -2x = 2x + -2x
Combine like terms: 3x + -2x = 1x
6 + 1x = 2x + -2x
Combine like terms: 2x + -2x = 0
6 + 1x = 0
Add '-6' to each side of the equation.
6 + -6 + 1x = 0 + -6
Combine like terms: 6 + -6 = 0
0 + 1x = 0 + -6
1x = 0 + -6
Combine like terms: 0 + -6 = -6
1x = -6
Divide each side by '1'.
x = -6
Simplifying
x = -6
</span>so the answer is x =-6
According to http://www.geteasysolution.com/3x+6=2x
A = P( 1 + rt)
A/P = 1 + rt
A/P - 1 = rt
t = (( A/P)) - 1)/r
t = (( 5500/1000) - 1)/(6.25/100
t = (5.5 - 1)/0.0625
t = 4.5/0.0625 = 72 years
Answer it will take 72 Years...
Hope it helps!!!!!
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