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postnew [5]
2 years ago
10

Convert 4.08 to a fraction. Help me please.

Mathematics
2 answers:
Travka [436]2 years ago
7 0

Answer:

4 8/10

Step-by-step explanation:

Since 4 is in the ones place, that means it will be a mixed fraction. Next, make the 0.8 into a fraction by making it into 80/100. Simplify, and then you will get 8/10. That's how you get 4.08 into 4 8/10.

Fofino [41]2 years ago
6 0

Answer:

4/8

Step-by-step explanation:0.n is = to 10. 4 is the numerator. So it would be 4/8

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A regular hexagon is rotated about its center. By which angle could the hexagon be rotated so that it is mapped onto itself?
Sauron [17]

Answer: 60

Step-by-step explanation:

5 0
3 years ago
There are 6 muffins in a package.How many packages will be needed to feed 48 people if each person has 2 muffins?
Paladinen [302]
16 packages would be needed



8 0
3 years ago
Read 2 more answers
You need 3 1/2 cups of flour for each batch of cupcakes. How many whole batches can make if you have 17 cups of flour? Show two
rosijanka [135]

<u>ANSWER:</u>

4 batches of cupcakes can be made.

<u>SOLUTION: </u>

Given, we need 3\frac{1}{2} cups of flour for each batch of cupcakes. And we have 17 cups of flour.

We need to find how many batches can be made.

1st way:

We will get the number of batches when we divide the available cups with cups required for one batch.

Available cups = 17 and required cups for one batch = 3\frac{1}{2} = \frac{7}{2} cups

number of batches = $\frac{17}{\frac{7}{2}}$

$=\frac{17}{1} \times \frac{2}{7}$

$=\frac{34}{7}$ = 4.857

As the number of batches can’t be fraction, we will neglect the fractional part.

2nd way:

Let the number of batches be x.

Then, cups of flour required for batches must be less than available flour

(x)(\frac{7}{2}) < 17

(x)(7) < (2)(17)

7x < 34

x < \frac{34}{7}

x < 4.857

As the number of batches must be an whole number, x becomes 4.

Hence, 4 batches of cupcakes can be made.

3 0
3 years ago
Given a joint PDF, f subscript X Y end subscript (x comma y )equals c x y comma space 0 less than y less than x less than 4, (1)
ioda

(1) Looks like the joint density is

f_{X,Y}(x,y)=\begin{cases}cxy&\text{for }0

In order for this to be a proper density function, integrating it over its support should evaluate to 1. The support is a triangle with vertices at (0, 0), (4, 0), and (4, 4) (see attached shaded region), so the integral is

\displaystyle\int_0^4\int_y^4 cxy\,\mathrm dx\,\mathrm dy=\int_0^4\frac{cy}2(4^2-y^2)=32c=1

\implies\boxed{c=\dfrac1{32}}

(2) The region in which <em>X</em> > 2 and <em>Y</em> < 1 corresponds to a 2x1 rectangle (see second attached shaded region), so the desired probability is

P(X>2,Y

(3) Are you supposed to find the marginal density of <em>X</em>, or the conditional density of <em>X</em> given <em>Y</em>?

In the first case, you simply integrate the joint density with respect to <em>y</em>:

f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_0^x\frac{xy}{32}\,\mathrm dy=\begin{cases}\frac{x^3}{64}&\text{for }0

In the second case, we instead first find the marginal density of <em>Y</em>:

f_Y(y)=\displaystyle\int_y^4\frac{xy}{32}\,\mathrm dx=\begin{cases}\frac{16y-y^3}{64}&\text{for }0

Then use the marginal density to compute the conditional density of <em>X</em> given <em>Y</em>:

f_{X\mid Y}(x\mid y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\begin{cases}\frac{2xy}{16y-y^3}&\text{for }y

6 0
3 years ago
The expression 38d+34 factored is
djyliett [7]
38d + 34 = 2(19d + 17)

Hope this helps.
4 0
3 years ago
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