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Ivan
2 years ago
11

Solution to 8n is less than72

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
7 0

Answer:

n is less than 9.

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When x = -3, then y = ?​
almond37 [142]

Step-by-step explanation:

the answer is y=-6 when x=-3

7 0
3 years ago
what is the difference between the mean and the median of the following distribution? {1,1,1,2,2,2,2,3,3,4,4,4,4,5,5,6,7,7,8,8,9
iren2701 [21]

The given distribution =

1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 7, 7, 8, 8, 9

To find mean, we have to add the given numbers and divide it by the total number of terms given.

Here 21 total numbers given.

Mean = (1+1+1+2+2+2+2+3+3+4+4+4+4+5+5+6+7+7+8+8+9) /21

= (88)/21 = 4.19 (Approximate upto two decimal place)

Median is the middle value of the distribution.

1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 7, 7, 8, 8, 9

There are 21 numbers given. So middle value is the number in the 11th position.

The number in the 11th position is 4.

So, the median of the distribution = 4

We have to find the difference between mean and median here. To find the difference we have to subtract mean and median.

Therefore, the required difference = 4.19 - 4 = 0.19

0.19 is the required answer here.

So, option b is correct.

3 0
4 years ago
Read 2 more answers
Can someone explain it too me why it is -8?.
Damm [24]

When a negative number is multiplied by a negative number it becomes positive, but when a positive number is multiplied by a negative number it goes back to negative. -2 X -2 is 4, and 4 x -2 is -8. Hope this helped.

8 0
4 years ago
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What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)
xxMikexx [17]
Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)

we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment  is 3√2

see the attached figure

3 0
3 years ago
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Use the following data to calculate the curve of the best-fit.
polet [3.4K]
The answer is D as in dog
7 0
3 years ago
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