I believe it is 48.
0+3=3
3+5=8
8+7=15
15+9=24
24+11=35
35+13=48
Answer:
2
Step-by-step explanation:
f(x)=2x^2+9x-5
When we are find how many times it intersects the x axis, we are finding the zero's. Set the equation equal to zero
0=2x^2+9x-5
Factor the equation
0 = (2x+1) (x-5)
2*1
1*-5 = -5
2*-5 +1*1 = -9
This checks for the first last and middle terms so we factored correctly
Then using the zero product property
2x+1 = 0 and x-5 =0
2x = -1 x=5
x = -1/2 and x=5
This function crosses the x axis 2 times
Angle-5 and angle-7 are 'vertical angles', so they're equal,
and we can write ...
<u>10x- 9 = 9x</u>
Subtract 9x from each side: x - 9 = 0
Add 9 to each side: <u> x = 9</u>
Now that we know what 'x' is, we can find the size of Angles-5 and -7 .
Angle-7 = 9x = 81° .
Now look at Angle-6 ... the one that's the answer to the problem.
Angle-6 and -7 together make a straight line, so they must
add up to 180°.
<u>Angle-6 + 81° = 180°</u>
Subtract 81° from each side: Angle-6 = <em>99° .</em>
Answer:
1, -6
Step-by-step explanation:
Since there are alike numbers, add them together.
4x+x= 5x
Now the function is: f(x)= 
+5x-6
The function is in 
+bx+c form.
So find the factors of a x c = b.
Factors of -6(a) that fits (b)5 is (-1,6).
Then you just factor it:
f(x)= +5x-6
(x-1)(x+6)
x-1= 0 x+6=0
+1 +1 -6 -6
x=1 x=-6
Those are the real zeroes: 1, -6
