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1 year ago

What is the difference between a regular and irregular quadrilateral?

Mathematics

1 answer:

docker41 [41]1 year ago

7 0

Answer:

Step-by-step explanation:

irregular

regular

what do you notice different?

the both have r, e, g, u, l, a, r, but one has ir at the beginning.

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32 ÷ 24 is EXACTLY equal to A) 1.3 B) 2.7 C) 4 3 D) 8 3

Gre4nikov [31]

A)1.33333333333333333333333333333333333333333 Repeating

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2 years ago

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A boat traveled 27 miles in 2 hours. At this rate, how many miles will the boat travel in

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6.75 miles per half hour !!!!!!!

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2 years ago

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The radius is 6 and the height is 15 what is the volume in terms of pi the shape is a cone

Alenkinab [10]

Answer:

565.49 or if rounded to the nearest tenth, 565.5

Explanation:

The formula for finding the volume of a cone is V=1/3Bh

B = pi times the radius squared

h = height

Substitute 6 for r and 15 for h.

V= 1/3· $\pi$ ·( $6^{2}$ )·15

Multiply.

V= 565.49 or 565.5 rounded to the nearest tenth.

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2 years ago

The school uses between 300 and 400 sheets of paper per school day. If paper costs the school $2.00 per 100 sheets, approximatel

Nady [450]

Answer:

Option A. $140.00

Explanation:

1. Using the minimun number of sheets of paper in the interval [300, 400]

a) Cost: $ 2.00 / 100 sheets

b) 300 sheets / day × $ 2.00 / 100 sheets = $ 6.00 / day

c) Approimately 20 school days per month:

$ 6.00 / day × 20 day = $ 120.00

2. Using the maximum number of sheets of paper in the interval [300, 400]

a) Cost: $ 2.00 / 100 sheets

b) 400 sheets / day × $ 2.00 / 100 sheets = $ 8.00 / day

c) Approimately 20 school days per month:

$8.00 / day × 20 day = $ 160.00

3. Middle value:

Calculate the middle value between $160.00 and $120.00

[$120.00 + $160.00] / 2 = $140.00

Thus, the answer is the option A.

7 0

2 years ago

Complete the table of inputs for the given function.

Alecsey [184]

Answer:

a. $x = \frac{3}{8}$

b. $g(0) = 3$

c. $x = 1$

d. $g(3) = -21$

Step-by-step explanation:

Given

$g(x) = 3 - 8x$

Solving (a): When g(x) = 0

Substitute 0 for g(x)

$g(x) = 3 - 8x$

$0 = 3 - 8x$

Solve for 8x

$8x = 3$

Solve for x

$x = \frac{3}{8}$

Solving (b): when x = 0

Substitute 0 for x

$g(x) = 3 - 8x$

$g(0) = 3 - 8 * 0$

$g(0) = 3 - 0$

$g(0) = 3$

Solving (c): When g(x) = -5

Substitute -5 for g(x)

$g(x) = 3 - 8x$

$-5 = 3 - 8x$

Solve for 8x

$8x = 3 + 5$

$8x = 8$

Solve for x

$x = \frac{8}{8}$

$x = 1$

Solving (d): When x = 3

Substitute 3 for x

$g(x) = 3 - 8x$

$g(3) = 3 - 8 * 3$

$g(3) = 3 - 24$

$g(3) = -21$

3 0

2 years ago