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2 years ago

What is the difference between a regular and irregular quadrilateral?

Mathematics

1 answer:

docker41 [41]2 years ago

7 0

Answer:

Step-by-step explanation:

irregular

regular

what do you notice different?

the both have r, e, g, u, l, a, r, but one has ir at the beginning.

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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.0 inches and a standard devi

alexira [117]

Answer: 0.8490

Step-by-step explanation:

Given : The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.0 inches and a standard deviation of 0.9 inches.

i.e. $\mu=30$ and $\sigma=0.9$

Let x denotes the lengths of aluminum-coated steel sheets.

Required Formula : $z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

For n= 36 , the probability that the average length of a sheet is between 29.82 and 30.27 inches long will be :-

$P(29.82$

∴ Required probability = 0.8490

3 0

3 years ago

Write the equation of the graph above

tekilochka [14]

There’s no graph add a pic <33

3 0

3 years ago

A hot air balloon rose from a height of 100 m to 400 m in 3 minutes. What was the balloon’s rate of change?

maria [59]

Answer:

1.666666667 meter per sec^2

Step-by-step explanation:

I feel like this is physic

using acceleration formla Vf-Vi/t

so 400-100/180sec

300/180

1.666666667 meter per sec^2

Hey im still learning tell me if you feel like im wrong OwO

7 0

3 years ago

Which value is a solution to the inequality 2x − 5 < −12?

Thepotemich [5.8K]

Answer:

-5.4 that's the answer

Step-by-step explanation:

I got you trust me

4 0

3 years ago

If a cup of coffee has temperature 97Â°C in a room where the ambient air temperature is 25Â°C, then, according to Newton's Law o

FinnZ [79.3K]

Answer:

The average temperature is $T_{a} = 81.95^oC$

Step-by-step explanation:

From the question we are told that

The temperature of the coffee after time t is $T(t) = 25 + 72 e^{[-\frac{t}{45} ]}$

Now the average temperature during the first 22 minutes i.e fro $0 \to 22$ minutes is mathematically evaluated as

$T_{a} = \frac{1}{22-0} \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx$

$T_{a} = \frac{1}{22} [25 t + 72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.$

$T_{a} = \frac{1}{22} [25 t - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.$

$T_{a} = \frac{1}{22} [25 (22) - 3240e^{[-\frac{22}{45} ]} - (- 3240e^{0} )]$

$T_{a} = \frac{1}{22} [550 - 1987.12 + 3240]$

$T_{a} = 81.95^oC$

8 0

3 years ago