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jek_recluse [69]
3 years ago
14

I really need help !!!!!!!!!!!

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0
Ln20+ln5=2ln x
ln(20*5) = ln x^2
ln 100 = ln x^2
100 = x^2
x = 10   second option
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Can somebody please help me? asap
Margarita [4]
Y= 2 slope= -3 this should be right.
6 0
3 years ago
The equation of a line is y=-2x+1. What is the equation of the line that is parallel to the first line and passes through (2,2)?
Murrr4er [49]

Answer:

The equation in slope-intercept form is y=-2x+6.

The equation in standard form is 2x+y=6.

The equation in point-slope form is y-2=-2(x-2).

Step-by-step explanation:

The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.

Parallel lines will have the same slope and different y-intercept.

Anyways the slope of y=-2x+1 is -2.

So the equation of our line we are looking for is -2.

So we know our equation is in the form y=-2x+b.

We must inf b using y=-2x+b with (x,y)=(2,2).

y=-2x  +b  with (x,y)=(2,2)

2=-2(2)+b

2=-4+b

Add 4 on both sides:

2+4=b

Simplify:

6=b

The equation is y=-2x+6.

Now it didn't say what form it wanted.

There are some forms I can give you like standard and point-slope form.

There is also general form but it is not too much different from standard form.

Standard form is ax+by=c where a,b, and c are integers if possible.

Point-slope form is y-y1=m(x-x1) where (x1,y1) is a point on the line and m is the slope.

So let's go for standard form (ax+by=c) first:

y=-2x+6

add 2x on both sides:

2x+y=6

This is standard form because it is in the form

ax+by=c.

Ok we know point (2,2) is on our line and we also know we have slope,m, is -2.

Point-slope form is

y-y1=m(x-x1)

y-2=-2(x-2)

8 0
3 years ago
Please answer this correctly for a brainliest ☺️
Dimas [21]
Hello I think the answer would be three.
5 0
3 years ago
Can someone help!! I will give brainlist
GalinKa [24]

Answer:

step-by-step explanation:

8x+2y=-22

8(0)+2y=-22

2y=-22

and now it is a two step equation

do the same thing to the other one  

8 0
3 years ago
15 points!
Phantasy [73]

Hi there! You are provided with two points, this is all you need to calculate the line's slope.


The equation for slope is:

\frac{y2 - y1}{x2 - x1}

\frac{10 - 8}{3 - 7} = -\frac{2}{4}

Slope: -2/4


Point slope form, or y-y1 = m(x - x1). All we have to do is take the x and y coordinates of either point, as well as the slope, and plug them into the equation.

y - 10 = -2/4(x - 3)


Write the equation in slope-intercept form (y=mx+b)

y - 10 = -2/4(x-3)\\y = -2/4(x-3) + 10\\y = -2/4x + 1.5 + 10\\y = -2/4x + 11.5


A) -2/4

B) y - 10 = -2/4(x - 3)

C) y = -2/4x + 11.5

8 0
2 years ago
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