Answer:
c
Step-by-step explanation:
If the dot product of the vectors is zero then they are perpendicular
(5, - 1) • (- 3, 6)
= (5 × - 3) + (- 1 × 6) = - 15 + (- 6) = - 15 - 6 = - 21 ≠ 0
Since product is not zero vectors are not perpendicular
B and e are you best choices hope this helps
30 mph would be a safe speed for you to drive.
Collisions are much more likely to occur when one driver travels greater speedy or more slowly than the alternative motors on the road. You have to input a throughway at or near the velocity of visitors except if the speed of site visitors exceeds the prison speed restrict.
A pedestrian has a 90 percent threat of survival if hit by a vehicle transferring at 30 km ph (18.64 mph). This decreases to 70 percent at 40 kmph (24. eighty five mph) and much less than 20 percent at 50kmph (31 mph). driving at decreased speeds also enables drivers to stop within a shorter distance.
Retaining high speeds on highways is straightforward, as roads are wider and traffic is usually mild. If there are signs that show a pace restriction of 80kph, use them as a guide and stick near them. it's also an excellent exercise to assess road situations and set your pace thus.
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The standard form of a quadratic equation is
, while the vertex form is:
, where (h, k) is the vertex of the parabola.
What we want is to write
as
First, we note that all the three terms have a factor of 3, so we factorize it and write:
.
Second, we notice that
are the terms produced by
, without the 9. So we can write:
, and substituting in
we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
The second step is to keep your x terms on the left and move the constant to the right by subtracting it from both sides.
