3 years ago

What is the second step in solving this equation by completing the square 3x^2+14x+8=0

1 answer:

8 0

The second step is to keep your x terms on the left and move the constant to the right by subtracting it from both sides.

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Vesna [10]

$(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =$

$= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}$

$= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}$

$= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}$

$= 2^{-16-12+28} \times 5^{10-8}$

$= 2^{0} \times 5^{2}$

$= 1 \times 25$

$= 25$

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3 years ago

polet [3.4K]

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3 years ago

TEA [102]

Its 16/48 i hope this helps

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3 years ago

VikaD [51]

Answer:

4 miles/1 day=56 miles/X days

X=56/4=14

Step-by-step explanation:

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3 years ago

8090 [49]

Answer:

the domain is the set of all x coordinations and the range is the set of all y coordinates. therefore, the answer is C.

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3 years ago