You have a system of equations

.
1. Substitude right side of second equation into the left side of the first equation:

.
2. Solve this equation:

.
3. Find y:
for

,
for

.
4. The solutions of the system are: (3,-12) and (5,-24).
Answer: Correct choice is A.
<span>Volume of the Sphere V = 4/3pi x r^3
So when diameter d = 3 inches => r = 1.5 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 1.5^3 = 14.14 in
So when diameter d = 8 inches => r = 4 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 4^3 = 268.03 in
So when diameter d = 9 inches => r = 4.5 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 4.5^3 = 381.63 in
value for option (a) is 3 x 14.14 = 42.42 inches
value for option (b) is 268.03 inches
value for option (c) is 381.63 / 2 = 190.815 inches
So the correct option would be (b)</span>
Answer:
![r=\sqrt[3]{\frac{3V}{4\pi}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D)
Step-by-step explanation:

We need to isolate 'r'
To isolate 'r' , first multiply by 3 on both sides
divide by 4pi on both sides

Take cube root on both sides
![\sqrt[3]{\frac{3V}{4\pi}}= r](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D%3D%20r)
Answer:
30? lol im guessing? idk...lol
Step-by-step explanation:
Answer:
Perimeter of triangle= sum of two sides and hypotenuse