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dybincka [34]
1 year ago
13

Solve the system of equations using elimination: -5x - 8y = -8 and

Mathematics
1 answer:
velikii [3]1 year ago
6 0
Hope this helps !!!!!!!!!!!!

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3 years ago
How do you solve this
AlladinOne [14]

Answer:

  • domain: all terms are defined for <em>all real numbers</em>
  • solution: x = 6

Step-by-step explanation:

Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6

6 0
3 years ago
120 students are interviewed.
RUDIKE [14]

Answer:

decimal

Step-by-step explanation:

u said give answer decimaa

7 0
2 years ago
EVALAUTE: 5|7 - 9| - 2=<br><br> a. -12<br> b. 0<br> c. 1<br> d. 8
alexandr1967 [171]
It’s d!!!!!!!!!!!!!!
3 0
3 years ago
Find the volume of the compound shape.​
jeyben [28]
<h3>Given:</h3>
  • Hemisphere ×2 or sphere
  • Cylinder
<h3>Solution:</h3><h3>Volume of the sphere:</h3>

v =  \frac{4}{3}  \pi {r}^{3}

v =  \frac{4}{3}  \times \pi \times  {2}^{3}

v = 33.51 \:  {m}^{3}

<h3>Volume of the cylinder:</h3>

v = \pi {r}^{2} h

v = \pi \times  {2}^{2}  \times 6

v = 75.40 \:  {m}^{3}

<h3>Total volume:</h3>

v = 75.40 + 33.51

v = 108.91 \:  {m}^{3}

<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>compound</u><u> </u><u>shape</u><u> </u><u>is</u><u> </u><u>108.91</u><u> </u><u>cubic</u><u> </u><u>meters</u><u>.</u>

4 0
1 year ago
Read 2 more answers
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