Step-by-step explanation:
Given equation is
2y = 3x + 10
3x - 2y + 10 = 0 .....i)
Any line parallel to line I) is
3x - 2y + k = 0 ......ii)
As the line two passes through the point ( 2 , - 5 ) Now substituting the values
3 * 2 - 2 * ( - 5) + k = 0
6 + 10 + k = 0
16 + k = 0
k = - 16
Now putting the value of k in equation two
3x - 2y + 16 = 0 is the required equation.
Hope it will help :)❤
The value of x is 60, as you wrote. The sum of all angles in a triangle is 180°.
The sum of all angles on a straight line is also 180°. So to find y, solve for the third angle of the triangle on the left.
50 + 60 = 110. 180-110 = 70°.
Now we know 2 of the 3 angles along the line (70° and x, 60°)
70 + 60 + y = 180
130 + y = 180
y = 50
Hope this helps. LMK if you have questions.
-2(3x - 9) + 5x = -10
-6x + 18 + 5x = -10
-6x + 5x = -10 - 18
-x = -28
x = 28 <===
Answer:
Around 11.9
Step-by-step explanation:
5.3n + 7.75 = 70.85
First subtract 7.75 on both sides.
5.3n = 63.1
Then divide both sides by 5.3
n=11.9 (I rounded to the nearest tenth.)
