Answer:
The coordinates of point s are (-3 , 3)
Step-by-step explanation:
* Lets revise some transformation
- If the point (x , y) translated horizontally to the right by h units
then the new point = (x + h , y)
- If the point (x , y) translated horizontally to the left by h units
then the new point = (x - h , y)
- If the point (x , y) translated vertically up by k units
then the new point = (x , y + k)
- If the point (x , y) translated vertically down by k units
then the new point = (x , y - k)
* Now lets solve the problem
∵ The vertices of triangle cde are c (-3 , 1) , d (-1 , 4) , e (-6 , 4)
∵ The new coordinates of two vertices are q (-1 , 6) , r (-6 , 6)
- The image of point d is q and the image of point e is r
∵ Point d = (-1 , 4) and point q = (-1 , 6)
∵ Point e = (-6 , 4) and point r = (-6 , 6)
- The x-coordinate has no change but the y-coordinate added by 2
∴ The triangle cde translated vertically up by 2 units to create the
congruent triangle sqr
- Lets translate point c two units up to find the coordinates of point s
∵ Point c = (-3 , 1)
∴ Poin s = (-3 , 1 + 2) = -3 , 3)
* The coordinates of point s are (-3 , 3)
in order to undo the fraction.
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