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3 years ago

20 POINT TO THE FIRST ANSWER + BRAINLIEST!!!

Mathematics

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love history [14]3 years ago

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The cost of aquiring the source is high, i believe

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A pole that is 2.5 m tall casts a shadow that is 1.47 m long. At the same time, a nearby tower casts a shadow that is 36.25 m lo

Roman55 [17]

The tower is 61.65 meters tall.

<u>SOLUTION: </u>

Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.

At the same time, a nearby tower casts a shadow that is 36.25 m long.

We have to find height of the tower.

Now, we know that,

$2.5 \mathrm{m} \text { tall } \rightarrow 1.47 \text { long shadow }$

Then, (let it be) n meter tall $\rightarrow$ 36.25 long shadow

So, by cross multiplication method,

$\Rightarrow \frac{2.5}{1.47}=\frac{n}{36.25}$

This can be written as,

$\Rightarrow 36.25 \times 2.5=1.47 \times n \rightarrow 1.47 n=90.625 \rightarrow n=61.649 \rightarrow n=61.65 \text{ m}$

Cross multiplications steps: (To find Single Variable)

Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
Set the two products equal to each other.
Solve for the variable.

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3 years ago

Find a polynomial of degree 3 with zeros of 4, 2i and -2i

andre [41]

$(x-4)(x-2i)(x+2i)=\\
(x-4)(x^2+4)=\\
x^3+4x-4x^2-16=\\
x^3-4x^2+4x-16$

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Y = kx - 8. The variable k can be any negative value.

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Question 101 3.1 What is the constant difference between the consecutive terms? < 612,18.24 e 7.14.21.28

rewona [7]

Answer:

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3 years ago

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11Alexandr11 [23.1K]

The absolute value of -72 is 72.

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Hope this helped!

~Just a girl in love with Shawn Mendes

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3 years ago

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