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andrew11 [14]
2 years ago
15

Helppppp pleaseeeeeee.

Mathematics
1 answer:
nadya68 [22]2 years ago
7 0

The area of the figure which consist the two semicircles and one rectangle with 4×8 ft dimensions is 44.6 ft².

<h3>What is the area of a rectangle?</h3>

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

A=a\times b

Here, (a)is the length of rectangle and (b) is the width of the rectangle

The given figure is in two parts. It is made with 2 semicircles and 1 rectangle. The length of the rectangle part is 8 ft and width of it is 4 ft long. Thus, the area of this part is,

A_r=8\times4\\A_r=32\rm\; ft^2

There are two semicircles, which make one complete circle. Thus, the area of this two semicircle with radius 2 ft, is,

A_c=\pi \times2^2\\A_c=12.57\rm\; ft^2

Thus, the area of this composite figure is,

A=A_r+A_c\\A=32+12.57\\A=44.57\rm\; ft^2\\A=44.6\rm\;ft^2

Thus, the area of the figure which consist the two semicircles and one rectangle with 4×8 ft dimensions is 44.6 ft².

Learn more about the area of rectangle here;

brainly.com/question/11202023

#SPJ1

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