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1 year ago

Find the surface area of the cylinder (please help)

Mathematics

2 answers:

o-na [289]1 year ago

5 0

2πr²+2πrh

Step-by-step explanation:

2/1*22/7*9/1*9/1+2*22/7*5/1*9/1

2*22*9+2*22*5*9

369+990

answer= 1359

Misha Larkins [42]1 year ago

4 0

Answer:

surface area we can also take it as total surface area

9 is the radius and 5cm is the height . as they asked total surface area we have to take the area of base so tht we can make it as

total surface area = csa of cylinder + area of base

we know that,

2pirh+pir²

pir(2h+r)

pir(2×5+9)

pir(10+9)

pir(19)

22/7×9×19

3762/7

=> 537.42 cm² is the answer.

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2 years ago

I need help on 1 & 2

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3 years ago

Currently a product has a gear ratio of 17:5, driver:driven. If the company wants to change the product to have the same gear ra

Sedbober [7]

Answer:

10 teeth must go on the driven gear

Step-by-step explanation:

Let the number of teeth be x

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8 0

2 years ago

write the equation of a line that passes through the points (5, -7) and is perpendicular to the line -2x + 6y = -4

VashaNatasha [74]

Answer:

y= -3x + 8

Step-by-step explanation:

Put -2x + 6y = -4 into slope-interceltp form

Take the negative reciprocal of the slope.

Use this reciprocal in point-slope form

and you have,

= y= -3x + 8

<em>(EDITED)</em> Steps:

2x+6y = -4

6y=2x - 4

y= 1/3x + 2/3

if two lines are perpendicular,

m1 * m2 + -1

1/3 * m2 = -1

m2 = -3

the line perpendicular to this line is

y = -3x + k ; k ∈ R

the line passes through the point (5,-7)

so,

-7 = -3. (5) +k

-7 = -15 + k

k = 8

∴the equation of a line that passes through the point (5,-7) and is perpendicular to the line -2x+6y=-4 is

y= -3x + 8

Hope this helps, have a nice day/night! :D

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