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Art [367]
4 years ago
10

Everbank Field, home of the Jacksonville Jaguars, is capable of seating 76,867 fans. The revenue for a particular game can be mo

deled as a function of the number of people in attendance, x. If each ticket costs $161, find the domain and range of this function.
Mathematics
1 answer:
Aleksandr [31]4 years ago
7 0
Given:
maximum seating 76,867 fans
cost of tickets $161
revenue: f(x) = 161x

y = 161x  

domain is the x values
range is the y values

using the formula: y = 161x where x = 76,867
y = 161(76,867)
y = 12,375,587

domain is 76,867
range is 12,375,587
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Solve for C:<br><br> C + 8 = -11<br><br> C = _____
stiv31 [10]
Well what +8 will be -11.
Let’s take this as positives.
8+11=19
Sooo
-19+8=-11
C=-19
7 0
3 years ago
Read 2 more answers
⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden
fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = \frac{354}{1219}

           n = sample of US adults  = 1291

           p = population proportion of adults

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                                    significance level are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ]

                         = [ \frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } , \frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } ]

                         = [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0
3 years ago
Amya spends 2 hours doing her homework. She daydreams about a robot that could do her homework in 10 minutes. If Amya did have t
ryzh [129]

Answer:

t=34.64 mins

Step-by-step explanation:

let Arya be A, Robot be B and Combined time be t

A+B=\frac{1}{t}\\A=\frac{1}{t+120}\\B=\frac{1}{t+10}\\\frac{1}{t+10}+\frac{1}{t+120}=t\\\frac{1}{t+10}=\frac{t+120-t}{t+120}\\t^2+120t=120t+1200\\t^2=1200\\t=34.6410

4 0
3 years ago
Put the following equation of a line into slope-intercept form, reducing all fractions. 6x+2y=8
djyliett [7]
6x+2y=8
2y=-6x +8
y=-3x+4
4 0
3 years ago
I need this please 64 points!
myrzilka [38]

Answer:

None. Wanda's work is correct.

Step-by-step explanation:

The first is correct.

3 0
3 years ago
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