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2 years ago

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Mathematics

1 answer:

Setler79 [48]2 years ago

3 0

Answer:

$\boxed{\sf{x=24}}$

Step-by-step explanation:

GIVEN:

To find the missing number in the proportion, you have to isolate it the term of x from one side of the equation.

$\sf{\dfrac{8}{7}=\dfrac{x}{21} }$

First, thing you do is switch sides.

$\sf{\dfrac{x}{21}=\dfrac{8}{7} }$

Multiply by 21 from both sides.

$\Longrightarrow: \sf{\dfrac{21x}{21}=\dfrac{8*21}{7} }$

Solve.

Multiply the numbers from left to right.

Use the order of operations.

PEMDAS stands for:

Parentheses
Exponents
Multiply
Divide
Add
Subtract

$\Longrightarrow: \sf{\dfrac{8*21}{7}=\dfrac{168}{7}=24 }$

$\Longrightarrow: \boxed{\sf{x=24}}$

Therefore, the final answer is x=24.

I hope this helps. Let me know if you have any questions.

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Hello :
answer B) 0
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1.5 per hour : 1.2 per hour

Step-by-step explanation:

The computation of the ratio is shown below:

For norma, the one pool would be

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And for albert, the one pool would be

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3 years ago

A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec

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Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

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P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

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P(A∩B) = P(A) x P(B)

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Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

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