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Lyrx [107]
2 years ago
10

BRAINLIEST+STARS

Mathematics
1 answer:
Evgen [1.6K]2 years ago
8 0

Answeri really cant see the bottom answers can you take a new picutre

Step-by-step explanation:

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Kevin is 3 times as old as Daniel. 4 years ago, Kevin was 5 times as old as Daniel. How old is Daniel now
matrenka [14]
<span>K = 3D. K - 4 = 5(D - 4). K - 4 = 5D - 20. K = 5D - 16. 3D = 5D - 16. 16 = 2D. D = 8. K = 3 x 8. K = 24.</span>
7 0
2 years ago
If DEF measures 32 inches, EF = 2x - 10 and DE= 4x find x and the measure of each segment.
azamat

Add EF and DE together to equal 32

2x-10 + 4x = 32

Combine like terms;

6x-10 = 32

Add 10 to each side:

6x = 42

Divide both sides by 6:

x = 42/6

X = 7

EF = 2x-10 = 2(7)-10 = 14-10 = 4

DE = 4x = 4(7) = 28

5 0
3 years ago
7n - 4 = 31. what is the value of the n​
Gelneren [198K]

Answer:

n = 5

Step-by-step explanation:

- Move all terms not containing  n  to the right side of the equation.

7n = 31 + 4

7n = 35

- Divide each term by  7  and simplify.

n = 5

i hope this helps :)

4 0
2 years ago
Read 2 more answers
Jill invested $500 in an account with a compound interest rate of 6%. cheryl invests $600 in an account with a compound interest
34kurt

The time taken by Jill and Cheryl to double their money is 12 years and 18 years respectively.

<h3>What is Algebra?</h3>

Algebra is the study of mathematical symbols and the rule involves manipulating these mathematical symbols.

Jill invested $500 in an account with a compound interest rate of 6%.

Cheryl invests $600 in an account with a compound interest rate of 4%.

The number of years each doubles their money. Using the relation of 72.

\rm t  = \dfrac{72}{r}

where r is the interest rate and t be the time

The time for the Jill will be

\rm t = \dfrac{72}{6}\\\\t = 12\\

The time for the Cheryl will be

\rm t = \dfrac{72}{4}\\\\t = 18\\

More about the Algebra link is given below.

brainly.com/question/953809

4 0
1 year ago
Simplify.Your answer should contain only positive exponents.
zhannawk [14.2K]

Step-by-step explanation:

1) r^3r^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=r^{3+3}

=r^6

2) 3k^3k^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=3k^{3+3}

=3k^6

3) \left(3b^2\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=3^3\left(b^2\right)^3

=27\left(b^2\right)^3

=27b^6

4) \left(2m^3\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=2^3\left(m^3\right)^3

=8\left(m^3\right)^3

=8m^{3\cdot \:3}

=8m^9

5) \frac{3r^3}{r^2}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

=3r^{3-2}

=3r^1

=3r

3 0
2 years ago
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