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Studentka2010 [4]
3 years ago
7

What are the x-intercept and y-intercept of the graph of y=13x−6 ?

Mathematics
1 answer:
mestny [16]3 years ago
3 0

Answer:

x intercept is 6/13

y intercept is -6

Step-by-step explanation:

x intercepted when y is zero.

y intecepted when x is zero...

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-144 is -1 x 2a x 3b what is the sum of a+b?
BigorU [14]
-144= -1×2a×3b
144=2a×3b
144= 6ab
24= ab

a,b could b any two factors that have a product of 24
For example a,b could = 6,4 or 8,3 or 24,1 

Answer:
This question is tricky because it could have multiple answers: for example is a,b= 6,4 then a+b= 10, but if a,b=24+1=25. So, the answer is that the sum of a+b varies depending on which 2 factors of 24 a and b are equal to. Does this make sense?
7 0
3 years ago
Lenox ironed 1/4 of the shirts over the weekend. she plans to split the remainder of the work equally over the next 5 evenings.
Arisa [49]
I'm not sure if I'm right but I got 21 don't depend on me to get ur answer correct tho Bc I'm not sure
3 0
3 years ago
Find the surface area of the rectangular and triangular prisms
harina [27]
Is there a picture to this????

if your just asking how to find  the area of something all you need to do is multiply all the numbers together and the total is the area.
For example if its 8cm,3cm,2cm all you need to do is multiply them together
8x3x2=48  so your area is 48cm
7 0
3 years ago
one evening, 2/3 of the students in Rick's class watched television. of this students, 3/8 watched a reality show. Of the studen
Dimas [21]

Answer:

0.0625 of the students recorded the show.

Step-by-step explanation:

2/3×3/8×1/4= the fraction of people who watched and recorded the show (0.0625)

6 0
3 years ago
Implicit differentiation of 1/x +1/y=5 y(4)= 4/19<br> y'(4)=?
Aneli [31]
\frac{1}{x} +\frac{1}{y} = 5\\\\x^{-1}+y^{-1}=5\\

Above, I changed the fraction form of x and y into exponential form so it is easier to see the differentiation. Now, we can differentiate:

-1x^{-2}+-1y^{-2}\frac{dy}{dx}=5\\\\\frac{-1}{x^2}-\frac{1}{y^2}\frac{dy}{dx}=5\\\\-\frac{1}{y^2}\frac{dy}{dx}=5+\frac{1}{x^2}\\\\\frac{dy}{dx}=-5y^2-\frac{y^2}{x^2}

Now that we have dy/dx, we can plug in the x, which is 4, and the y, which is 4/19. We know these values of x and y because your question stated y(4) = 4/19.

\frac{dy}{dx}=-5(\frac{4}{19})^2-\frac{(\frac{4}{19})^2}{(4)^2}\\\\\frac{dy}{dx}=-5(\frac{16}{361})-\frac{(\frac{16}{361})}{16}\\\\\frac{dy}{dx}=\frac{-80}{361}-\frac{1}{361}\\\\\frac{dy}{dx}=\frac{-81}{361}
5 0
3 years ago
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