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3 years ago

For f(x) = 3x +1 and g(x) = x² - 6, find (f/g)(x)

Mathematics

1 answer:

Paha777 [63]3 years ago

8 0

Answer:

Step-by-step explanation:

$\frac{f(x)}{g(x)} =\frac{3x+1}{x^{2}-6 }$

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Help ASAP Please with this math problem. Just look at the picture.

kondaur [170]

${( \sqrt{9)} }^{2}$

$={3}^{2}$

$= 9$

${9}^ \frac{1}{2}$

$= ({3}^{2} ) ^{ \frac{1}{2} }$

$= 3 ^{1}$

$= 3$

8 0

3 years ago

What is the ratio of the perimeter of ΔHKO to the perimeter of ΔFGO

Lera25 [3.4K]

Answer:

Part 1) The ratio of the perimeter of ΔHKO to the perimeter of ΔFGO is $\frac{1}{2}$

Part 2) The ratio of the area of ΔKHO to the area of ΔGFO is $\frac{1}{4}$

Step-by-step explanation:

Part 1)

we know that

If two figures are similar , then the ratio of its perimeters is equal to the scale factor

In this problem

Triangles HKO and FGO are similar by AAA Theorem

Find the scale factor

The scale factor is equal to the ratio of its corresponding sides

$\frac{4}{8}=\frac{7}{14}=\frac{1}{2}$

Part 2) Find the ratio of the area of ΔKHO to the area of ΔGFO

Area of ΔKHO

$A=4*7/2=14\ units^{2}$

Area of ΔGFO

$A=8*14/2=56\ units^{2}$

The ratio of its areas is equal to

$\frac{14}{56}=\frac{1}{4}$

Alternative Method

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

In this problem we have that

The scale factor is $\frac{1}{2}$

squared the scale factor

$(\frac{1}{2})^{2}=\frac{1}{4}$ ----> is correct

7 0

3 years ago

PLEASE HELP NEED THIS DONE ASAP

kenny6666 [7]

Answer:

The area of rhombus PQRS is 120 m.

Step-by-step explanation:

Consider the rhombus PQRS.

All the sides of a rhombus are equal.

Hence, PQ = QR = RS = SP = 13 m

The diagonals PR and QS bisect each other.

Let the point at of intersection of the two diagonals be denoted by <em>X</em>.

Consider the triangle QXR.

QR = 13 m

XR = 12 m

The triangle QXR is a right angled triangle.

Using the Pythagorean theorem compute the length of QX as follows:

QR² = XR² + QX²

QX² = QR² - XR²

= 13² - 12²

= 25

QX = √25

= 5 m

The measure of the two diagonals are:

PR = 2 × XR = 2 × 12 = 24 m

QS = 2 × QX = 2 × 5 = 10 m

The area of a rhombus is:

$\text{Area}=\frac{1}{2}\times d_{1}\times d_{2}$

Compute the area of rhombus PQRS as follows:

$\text{Area}=\frac{1}{2}\times PR\times QS$

$=\frac{1}{2}\times 24\times 10\\\\=120$

Thus, the area of rhombus PQRS is 120 m.

5 0

3 years ago

Multiply.

Alik [6]

Answer:

Simplify the expression.

Exact Form:

77 /10

Decimal Form:

7.7

Mixed Number Form:

Hope This Helps

8 0

3 years ago

What is 4 plus 4 hehe

Lynna [10]

Answer:

(plus = +)

-,-

Step-by-step explanation:

<h2>Hope it helps! </h2>

4 0

3 years ago