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3 years ago

NEED THIS ANSWER ASAP!!!!! 4m + 3(n + 7m)

Mathematics

1 answer:

dlinn [17]3 years ago

4 0

Answer:

25m + 3n.

Step-by-step explanation:

Applying the Distrubutive Property will make this easier:

Simplified Version:

4m + 3n + 21m

Adding "M's"

25m + 3n

Thus, the simplified answer is 25m + 3n.

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MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!

Marina CMI [18]

Question 2. :

8^2 = 64 and 9^2 = 81, therefore the square root of 65 falls between these two values, 8 and 9, 64<65<81

Question 3. :

13^2 = 169 and 14^2 = 196, the correct answer is square root of 175, because 169<175<196

Hope this helps, you only need to know the squared values and square roots.

8 0

4 years ago

The probability that a customer's order is not shipped on time is 0.06. A particular customer places three orders, and the order

charle [14.2K]

Answer:

a) There is a 83.06% probability that all orders are shipped on time.

b) There is a 15.90% probability that exactly one order is not shipped ontime.

c) The probability of at least two orders being late is 1.02% + 0.02% = 1.04%.

Step-by-step explanation:

Probability:

What you want to happen is the desired outcome.

Everything that can happen iis the total outcomes.

The probability is the division of the number of possible outcomes by the number of total outcomes.

In our problem, there is:

-A 6% probability that a customer's order is not shipped on time.

-A 94% probability that a customer's order is shipped on time.

We have these following orders:

O1 - O2 - O3.

(a) What is the probability that all are shipped on time?

The probabilities that each order is shipped on time are O1 = 0.94, O2 = 0.94 and O3 = 0.94. So:

$P = (0.94)^{3}$ = 0.8306

There is a 83.06% probability that all orders are shipped on time.

(b) What is the probability that exactly one is not shipped ontime?

The order's can be permutated. What this means? It means that we can have O1 late and O2,03 on time, O2 late and O1,O3 on time and O3 late and O1, O2 on time. We have a permutation of 3 elements(the orders) with 2 and 1 repetitions(2 on time and one late).

The probability that an order is late is:

$P = (0.94)^{2}(0.06)$ = 0.053 for each permutation

Considering the permutations:

$P = 0.053*p^{3}_{2,1} = 0.053\frac{3!}{2!*1!} = 0.053*3 = 0.1590$

There is a 15.90% probability that exactly one order is not shipped ontime.

(c) What is the probability that two or more orders are not shipped on time?

P = P1 + P2, where P1 is the probability that two orders are late and P3 is the probability that all three orders are late.

Considering the permutations, the probability that two orders are late is:

$P_{1} = p^{3}_{2,1}*(0.94)*(0.06)^{2} = 3*(0.94)*(0.06)^{2} = 0.0102$

There is a 1.02% probability that two orders are late

$P_{2} = (0.06)^3 = 0.0002$

There is a 0.02% probability that all three orders are late.

The probability of at least two orders being late is 1.02% + 0.02% = 1.04%.

5 0

3 years ago

The “new look” of the cereal boxes has a length that is three more than two times the width, x, and a height that is one more th

jok3333 [9.3K]

The first option is correct. For the following question, the simplified expression for the volume is 8x3 + 14x2 + 3x.

5 0

3 years ago

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Simplify the expression<br> 8s - 11s + 6

raketka [301]

8 s -11 s + 6= - 3 s + 6=
= 3( - s +2)

6 0

4 years ago

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Below is the graph of f(x)=2In(x). how would you describe the graph of g(x)=4In(x)

Andreyy89

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now... with that template in mind, let's see yours

$\bf \begin{array}{llll}
g(x)=&4ln(x)\implies &2(2)ln(x)\\
&\uparrow &\uparrow \\
&A&A
\end{array}$

A is twice as large as in f(x), thus the graph shrinks twice as much in g(x)

7 0

4 years ago

Read 2 more answers