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2 years ago

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The probability that Lexie is on time for a given class is 95%. If there are 32 classes during the semester, what is the best es

timate of the number of times out of 32 that Lexie is on time to class? Round your answer to the nearest integer.

1 answer:

nignag [31]2 years ago

7 0

Answer:

between 31 and 29 classes

Step-by-step explanation:

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HELP IM GIVING BRAINLIEST!!!

Kobotan [32]

Answer:

I think H

Step-by-step explanation:

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3 years ago

Read 2 more answers

In-s [12.5K]

Answer:

I got 40210.1

Step-by-step explanation:

4,567.89+7,894.56=12462.45

12462.45+1,232.45=13694.9

13694.9+1,474.10=15169

15169+2,585.20=17754.2

17754.2+3696.36=21450.56

21450.56+3,214.56=24665.12

24665.12+6,545.65=31210.77

31210.77+7,898.78=39109.55

39109.55+1.100.55=40210.1

5 0

3 years ago

Write an equation to represent function A

maw [93]

Answer:

y = 312x + 2

Step-by-step explanation:

According to y = mx + b, m stands for slope and b stands for y-intercept. Let us find the y-intercept. To find the y-intercept, the x should be zero in (x, y).

(x, y)

(0, 2) ---> y-intercept (b)

Now that we have found the y-intercept, we will now find the slope by using its formula.

Slope formula:-

m = y2 - y1 / x2 - x1

Pick two random (x, y). I will pick the first and last pairs.

(0, 2) and (4, 1250)

Now plug these two pairs in the formula.

m = y2 - y1 / x2 - x1

m = 1250 - 2 / 4 - 0

m = 1248 / 4

m = 312

This means that the slope (m) is 312. Now put that in y = mx + b form.

y = mx + b

y = 312x + 2

Both of the forms are the same. Hope this helps, thank you :) !!

6 0

3 years ago

Steven works at the Pi Day food truck and he gets paid $9 per hour x. If 1 point

vitfil [10]

P(x) =9x +30

the tips are a flat rate so it’s a constant 30 while the 9 per hour is dependent on the hours worked which is why it is attached to x as a coefficient

8 0

3 years ago

The profit P (in thousands of dollars) for a company spending an amount s (in thousands of dollars on advertising is

sattari [20]

Answer:

The company should spend $40 to yield a maximum profit.

The point of diminishing returns is (40, 3600).

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

<u>Algebra I</u>

Coordinate Planes

Coordinates (x, y) → (s, P)

Functions

Function Notation

Terms/Coefficients

Factoring/Expanding

Quadratics

<u>Algebra II</u>

Coordinate Planes

Maximums/Minimums

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

1st Derivative Test - tells us where on the function f(x) does it have a relative maximum or minimum

Critical Numbers

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle P = \frac{-1}{10}s^3 + 6s^2 + 400$

<u>Step 2: Differentiate</u>

[Function] Derivative Property [Addition/Subtraction]: $\displaystyle P' = \frac{dP}{ds} \bigg[ \frac{-1}{10}s^3 \bigg] + \frac{dP}{ds} [ 6s^2 ] + \frac{dP}{ds} [ 400 ]$
[Derivative] Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle P' = \frac{-1}{10} \frac{dP}{ds} \bigg[ s^3 \bigg] + 6 \frac{dP}{ds} [ s^2 ] + \frac{dP}{ds} [ 400 ]$
[Derivative] Basic Power Rule: $\displaystyle P' = \frac{-1}{10}(3s^2) + 6(2s)$
[Derivative] Simplify: $\displaystyle P' = -\frac{3s^2}{10} + 12s$

<u>Step 3: 1st Derivative Test</u>

[Derivative] Set up: $\displaystyle 0 = -\frac{3s^2}{10} + 12s$
[Derivative] Factor: $\displaystyle 0 = \frac{-3s(s - 40)}{10}$
[Multiplication Property of Equality] Isolate <em>s </em>terms: $\displaystyle 0 = -3s(s - 40)$
[Solve] Find quadratic roots: $\displaystyle s = 0, 40$

∴ <em>s</em> = 0, 40 are our critical numbers.

<u>Step 4: Find Profit</u>

[Function] Substitute in <em>s</em> = 0: $\displaystyle P(0) = \frac{-1}{10}(0)^3 + 6(0)^2 + 400$
[Order of Operations] Evaluate: $\displaystyle P(0) = 400$
[Function] Substitute in <em>s</em> = 40: $\displaystyle P(40) = \frac{-1}{10}(40)^3 + 6(40)^2 + 400$
[Order of Operations] Evaluate: $\displaystyle P(40) = 3600$

We see that we will have a bigger profit when we spend <em>s</em> = $40.

∴ The maximum profit is $3600.

∴ The point of diminishing returns is ($40, $3600).

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation (Applications)

5 0

2 years ago