Equations of straight lines are in the form y = mx + c (m and c are numbers). m is the gradient of the line and c is the y-intercept (where the graph crosses the y-axis).
Answer: first option.
Step-by-step explanation:
The ratio of the area of the triangles can be calculated as following:

Where
is the lenght of the given side of the smaller triangle and
is the lenght of the given side of the larger triangle.
Therefore:

It can be written as following:

The ratio of the perimeter is:

Where
is the lenght of the given side of the smaller triangle and
is the lenght of the given side of the larger triangle.
Therefore:

It can be written as following:

Answer:
Account B would be the best option
Step-by-step explanation: