The x -intercepts occur when f(x) =0
So,
(x-4)^2 = x^2 -8x + 16 -3 =0
x^2 -8x + 13 =0
Solving by the quadratic formula
x1 = 5.7321
x2 = 2.2679
Answer:
see attached
Step-by-step explanation:
The x-coordinate of the vertex is given by ...
x = -b/(2a)
for f(x) = ax^2 +bx +c.
We see that the vertex is at x = 1, and we are given a = -16. Then we can find "b" from ...
1 = -b/(2(-16))
32 = b
We know the y-intercept of the equation is 5 (the starting height), so the equation must be ...
h(t) = -16t^2 +32t +5 . . . . . matches the last choice
Answer:
-23
Step-by-step explanation:
Answer:
1st, 3rd and 4th
Step-by-step explanation:
Only 2nd is false
Answer:
12 months, so 1 year
Step-by-step explanation: