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Viktor [21]
3 years ago
12

13) 3 bags of Brand X dog food and 4 bags of Brand Y dog food costs $18,

Mathematics
1 answer:
GuDViN [60]3 years ago
4 0

Answer:

the cost of brand x dog food is $2

Step-by-step explanation:

Let brand X dog food be represented as A

Let Brand Y dog food be represented as B

3 bags of Brand X dog food and 4 bags of Brand Y dog food costs $18,

3A+4B=18

4 bags of Brand X dog food and 3 bags of Brand Y dog food costs

$17.

4A+3B= 17

  • 3A+4B=18
  • 4A+3B= 17

Using Elimination method

Multiply

  • 3A+4B=18 by coefficient of B in equ ii (3)  = 9A+12B=54
  • 4A+3B= 17 by coefficient of B in equ i (4)  = 16A+12B=68
  • subtract equation i from equation ii, since sign is the same in both equations
  • 9A+12B-(16A+12B)= 54-68
  • open bracket
  • 9A+12B-16A-12B= 54-68= -14
  • 9A-16A+12B-12B= -14
  • -7A= -14
  • divide both sides by -7

A = -14/-7= 2

Since the brand X dog food is represented as A

the cost of brand x dog food is $2

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Greeley [361]

Answer:

B

Step-by-step explanation:

Thank me later

7 0
2 years ago
Serena’s average speed during her training run was 8 kilometers per hour over the 2 hours that she ran. What was the total dista
kogti [31]
D=rt
d= 8 x 2
d = 16 km

<span>D. 16 km</span>
7 0
3 years ago
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The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with
pochemuha

Answer:

a)17.92

b) 16.83 .... 21.17

Step-by-step explanation:

ρ→   z

0.14 = -1.080319341

-1.080 = (x - 19)/1 = 17.92

~~~~~~~~~~~~~~~~~~

3% / 2 = 1.5%

1.5% - 98.5%

ρ→   z

0.015 = -2.170090378 ....  -2.17 = (x-19) =16.83

0.985 = 2.170090378  ....   2.17 = (x-19) =21.17

8 0
3 years ago
Please Help! Multiple Choice!
Katyanochek1 [597]

Using the z-distribution, the p-value would be given as follows:

b) 0.0086.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis we test if the means are equal, hence:

H_0: \mu_D - \mu_C = 0

At the alternative hypothesis, it is tested if they are different, hence:

H_1: \mu_D - \mu_C \neq 0

<h3>What are the mean and the standard error for the distribution of differences?</h3>

For each sample, they are given as follows:

  • \mu_D = 12, s_D = \frac{5.2}{\sqrt{73}} = 0.6086
  • \mu_C = 14, s_C = \frac{4.1}{\sqrt{81}} = 0.4556

Hence, for the distribution of differences, they are given by:

  • \overline{x} = 12 - 14 = -2.
  • s = \sqrt{0.6086^2 + 0.4556^2} = 0.76

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

z = \frac{\overline{x} - \mu}{s}

z = \frac{-2 - 0}{0.76}

z = -2.63.

Using a z-distribution calculator, for a two-tailed test, with z = -2.63, the p-value is of 0.0086.

Hence option B is correct.

More can be learned about the z-distribution at brainly.com/question/13873630

#SPJ1

4 0
2 years ago
Yo SQ here are the rest please and thank you.
azamat

Answer:make me brainliest

Step-by-step explanation:

This is easy wanna learn it go to question cove and search it

7 0
3 years ago
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