Our three consecutive integers can be represented as
X ← <em>first integer</em>
X + 1 ← <em>second integer</em>
X + 2 ← <em>third integer</em>
Since the sum of our three consecutive integers is 345, our equation will read
X + X + 1 + X + 2 = 345
When we simplify on the left, our equation will now read
3x + 3 = 345
-3 -3 ← subtract 3 on both sides
3x = 342 ← divide both sides by 3
X = 114
first integer = 114
second integer = 114 + 1 = 115
third integer = 114 + 2 = 116
Therefore, the three consecutive integers are 114, 115, and 116.