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REY [17]
2 years ago
5

Which equation can be solved by using this system of equations? startlayout enlarged left-brace 1st row y = 3 x superscript 5 ba

seline minus 5 x cubed 2 x squared minus 10 x 4 2nd row y = 4 x superscript 4 baseline 6 x cubed minus 11 endlayout 3 x superscript 5 baseline minus 5 x cubed 2 x squared minus 10 x 4 = 0 3 x superscript 5 baseline minus 5 x cubed 2 x squared minus 10 x 4 = 4 x superscript 4 baseline 6 x cubed minus 11 3 x superscript 5 baseline 4 x superscript 4 baseline x cubed 2 x squared minus 10 x minus 7 = 0 4 x superscript 4 baseline 6 x cubed minus 11 = 0
Mathematics
1 answer:
Mariulka [41]2 years ago
3 0

An equation which can be used to solve the given system of equations is 3x⁵ - 5x³ + 2x² - 10x + 4 = 4x⁴ + 6x³ - 11.

<u>Given the following data:</u>

y = 3x⁵ - 5x³ + 2x² - 10x + 4

y = 4x⁴ + 6x³ - 11

<h3>What is a system of equations?</h3>

A system of equations can be defined an algebraic equation that only has two (2) variables and can be solved simultaneoulsy.

Equating the given equations, we have:

y = y

3x⁵ - 5x³ + 2x² - 10x + 4 = 4x⁴ + 6x³ - 11

3x⁵ - 5x³ + 2x² - 10x + 4 - (4x⁴ + 6x³ - 11) = 0

3x⁵ - 5x³ + 2x² - 10x + 4 - 4x⁴ - 6x³ + 11 = 0

3x⁵ - 5x³ + 2x² - 10x + 4 - 4x⁴ - 6x³ + 11 = 0

3x⁵ - 4x⁴ - 11x³ + 2x² - 10x + 15 = 0

Read more on equations here: brainly.com/question/13170908

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Explain the
Ivenika [448]

Answer:

a2=12 (the second term of the sequence is 12)

Step-by-step explanation:

a5=324

If the term to term rule is multiply by any number, we deal with geometrical sequence

The formula you should use is an= a1*r^(n-1)  where n is the number of the term which we know. In our case we know

a5, so use 5 instead of n

Then you have a5=a1*r^4 where r is the number 3 (because each next term is greater than previous in 3 times)

a5=324

324= a1*3^4

324=a1*81

a1=4 (We find the first term of sequence, because having it you can easily search for every term )

Return to the formula an= a1*r^n-1

Now search for the second term using 2 instead of n in the formula

a2= a1*r^1

a2=a1*r, a1=4, r=3

a2=4*3=12

7 0
2 years ago
8 times of the eight term of an arithmetic progression is equal to 12 times of the twelfth term. find its first term if the comm
Ilya [14]

Answer:

a₁ = 38

Step-by-step explanation:

Given AP, where:

  • 8a₈ = 12a₁₂
  • d = -2,
  • a₁ = ?

=============

<h3>Solution</h3>

aₙ = a₁ + (n-1)d

  • a₈ = a₁ + 7d = a₁ + 7*(-2) = a₁ - 14
  • a₁₂ = a₁ + 11d = a₁ + 11*(-2) = a₁ - 22

8a₈ = 12a₁₂

  • 8(a₁ - 14) = 12(a₁ - 22)
  • 2(a₁ - 14) = 3(a₁ - 22)
  • 2a₁ - 28 = 3a₁ - 66
  • 3a₁ - 2a₁ = -28 + 66
  • a₁ = 38
6 0
3 years ago
10) xc = rd , for x<br><br> Help plz
ExtremeBDS [4]

Answer:

x = rd/c

Step-by-step explanation:

xc = rd

xc/c = rd/c

x = rd/c

8 0
2 years ago
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