4.a) 2x=7*3
2x=21
x=21/2 OR
x=10.5
4.b)5x=25*6
5x=150
x=150/5
x=30
4.c)4x=5*14
4x=70
x= 70/4
x=17.5
4.d)4x=9*3
4x=27
X=27/4
X=6.75
4.e)x=0.05*3
X=0.15
4.f)x=0.25*7
X=1.75
4.g)x=0.4*1.5
X=0.6
4.h)x=0.7*2.2
X=1.54
5a)x/7=7-3
X/7=4
X=4*7
X=28
B)2x/5=3+8
2x/5=11
2x=11*5
2x=55
X=55/2
X=27.5
C)2x/3=74-26
2x/3=48
2x=48*3
2x=144
X=72
(I can’t finish all but it is the same method )
Answer:
imma need my points back
Step-by-step explanation:
Answer:
The correct answer is option (E)
Step-by-step explanation:
Solution to the question
Let us recall from given question that,
H0:p=0.80
Ha:p≠0.80 (which is the two tailed test)
For the p-value we have,
P-value: Let us assume that the null hypothesis is true, then the probability of observing the sample statistics or the more extreme,
Therefore if p= 0.80, the probability of observing or detecting proportion of samples is of at least 0.84 or at most 0.76 is 0.273.
