There are 12 months in a year, if we chose 25 random dates we'll have two dates per month
2x12=24
and one extra day that will fit in another month.
The principle used for this kind of problem is the<em> pigeonhole principle</em>, supposing we have a number k of pigeonholes and n pigeons to be placed in them, If the number of pigeons is bigger than the pigeonholes, there will be at least one pigeonhole with more than one pigeon.
This happens with our problem, 25 days is a larger number than 12 months two times (24), this means we'll choose at least one month three times.
I hope you find this information useful! good luck!
Given that a hyena runs 2 kilometers for every 25 kilometer a mouse runs.
Now we need to select from the drop-down menu to correctly complete the statement. Where given statement is "The hyena runs kilometers for every kilometer the mouse runs."
"every kilometer" indicates we need to find number of kilometers for hyena when mouse runs 1 kilometer.
To find that we will divide number of kilometers of hyena by number of kilometers of mouse that is divide 2 by 25.
2/25=0.08
Hence final answer will be :
"The hyena runs 0.08 kilometers for every kilometer the mouse runs."