Answer:

Step-by-step explanation:
(cylinder)
(rectangular prism)
(whole shape)
Answer: Choice A
The number line graph is visually showing every number that is 19 or smaller; hence 
Note the use of a closed or filled in circle at the endpoint (in contrast to an open circle). This indicates we are including the endpoint 19 as part of the solution set, and that's why we go for "or equal to" as part of the inequality sign.
Answer:

We divide both sides by 100000 and we got:

Now we can apply natural logs on both sides;

And then the value of t would be:

And rounded to the nearest tenth would be 9.2 years.
Step-by-step explanation:
For this case since we know that the interest is compounded continuously, then we can use the following formula:

Where A is the future value, P the present value , r the rate of interest in fraction and t the number of years.
For this case we know that P = 100000 and r =0.12 we want to triplicate this amount and that means
and we want to find the value for t.

We divide both sides by 100000 and we got:

Now we can apply natural logs on both sides;

And then the value of t would be:

And rounded to the nearest tenth would be 9.2 years.
- Using
substitution
means you are going to solve one equation for one variable and substitute with
its value in the other equation in order to get also an equation with one
variable.
Answer:
y = 0x + 70
y = 4x + 15
y = 6x + 0
Step-by-step explanation: