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3 years ago

13

Need help with these. 11th grade algebra 2 class. thanks

1 answer:

OlgaM077 [116]3 years ago

3 0

15) x=31/10
16)x=2
17)x=16/3
18)x=-2
19)2.5 hours
20) 32 hours

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18. An urn contains 3 red balls, 2 green balls and 1 yellow ball. Three balls are selected at random and without replacement fro

Goryan [66]

Answer:

27.77%

Step-by-step explanation:

The probability of not drawn a red ball is 3/6. The probability of not drawn a green ball is 4/6, and the probability of not drawn a yellow ball is 5/6. So, the probability of not drawn at least one color is the multiplication of the probabilities of each color, so (3/6)*(5/6)*(4/6) = 0.2777.

5 0

3 years ago

F(x)=4^x and g(x)=4^x+2

dsp73

Given:

The two functions are:

$f(x)=4^x$

$g(x)=4^x+2$

To find:

The type of transformation from f(x) to g(x) in the problem above and including its distance moved.

Solution:

The transformation is defined as

$g(x)=f(x+a)+b$ .... (i)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left.
If a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up.
If b<0, then the graph shifts b units down.

We have,

$f(x)=4^x$

$g(x)=4^x+2$

The function g(x) can be written as

$g(x)=f(x)+2$ ...(ii)

On comparing (i) and (ii), we get

$a=0,b=2$

Therefore, the type of transformation is translation and the graph of f(x) shifts 2 units up to get the graph of g(x).

3 0

3 years ago

Which statement is true about the marginal frequencies

Tcecarenko [31]

Answer:

D

Step-by-step explanation:

If U add up all the people who played sports and all the 10th graders u will get 191 and 97 and it just said I got it right

3 0

3 years ago

Read 2 more answers

Please someone what is the total surface area of this pryamid

Dimas [21]

Answer:

$\large\boxed{C.\ (25+25\sqrt3)\ in^2}$

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

$A_S=a^2$

a - length of side

The formula of an area of an equilateral triangle:

$A_T=\dfrac{a^2\sqrt3}{4}$

a - length of side

Clculate the areas:

SQURE:

$A_S=x^2\ in^2$

TRIANGLE:

$A_T=\dfrac{x^2\sqrt3}{4}\ in^2$

The SURFACE AREA of a square pyramid:

$S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3$

Put x = 5:

$S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2$

7 0

3 years ago

One of the tables shows a proportional relationship. Graph the line representing the proportional relationship from this table.

sergey [27]

Answer: have you found the answer if so please tell me

6 0

3 years ago

Read 2 more answers