Answer:
P = 499.2 Watt
Step-by-step explanation:
Who says V1=V2?
if we simplify we get
(2/3)pir₁³=12pir₂²
for V1 to equal V2
a.
solve for r₁ to find r₁ as a function of r₂
(2/3)pir₁³=12pir₂²
times 3/2 both sides and divide by pi
r₁³=18r₂²
cube root both sides
r₁=∛(18r₂²)
if solve for r₂
(2/3)pir₁³=12pir₂²
divide by 12pi both sides
(1/18)r₁³=r₂²
squer root both sides
√((1/18)r₁³)=r₂
double radius of pond which is r1
√((1/18)r₁³)=r₂
r₁ turns to 2r₁ to double radius
√((1/18)(2r₁)³)=r₂double
√(8(1/18)(r₁)³)=r₂double
(√8)(√((1/18)(r₁)³))=r₂double
√((1/18)r₁³)=r₂ so
(√8)(r₂)=r₂double
(2√2)(r₂)=r₂double
the radius of the tank is multipled by 2√2
The equation of the line that passes through the points (2,1) and (5,-8) is
y = -3x + 7
Answers:
- C) x = plus/minus 11
- B) No real solutions
- C) Two solutions
- A) One solution
- The value <u> 18 </u> goes in the first blank. The value <u> 17 </u> goes in the second blank.
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Explanations:
- Note how (11)^2 = (11)*(11) = 121 and also (-11)^2 = (-11)*(-11) = 121. The two negatives multiply to a positive. So that's why the solution is x = plus/minus 11. The plus minus breaks down into the two equations x = 11 or x = -11.
- There are no real solutions here because the left hand side can never be negative, no matter what real number you pick for x. As mentioned in problem 1, squaring -11 leads to a positive number 121. The same idea applies here as well.
- The two solutions are x = 0 and x = -2. We set each factor equal to zero through the zero product property. Then we solve each equation for x. The x+2 = 0 leads to x = -2.
- We use the zero product property here as well. We have a repeated factor, so we're only solving one equation and that is x-3 = 0 which leads to x = 3. The only root is x = 3.
- Apply the FOIL rule on (x+1)(x+17) to end up with x^2+17x+1x+17 which simplifies fully to x^2+18x+17. The middle x coefficient is 18, while the constant term is 17.
It equals 18.32 you can go to calculatorsoup.com and it shows you
