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andrezito [222]
4 years ago
15

What is an equation of the line that passes through the point

Mathematics
1 answer:
Ahat [919]4 years ago
3 0

Step-by-step explanation:

Parallel lines have the same slope.

x -3y = 21

y = (21-x)/-3 ==== y = 1/3x -7

Substitute the values,

y = mx + c

5 = (1/3)(-6) + c

5 = -2 + c

c = 7

Thus, the equation is y = 1/3x + 7

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1. What is the solution to the equation<br> below?<br> -5/4x + 2/5 = -13/30
Artemon [7]

Answer:

2/3 or .6 repeating

Step-by-step explanation:

6 0
3 years ago
What is the square root of -6.76
mojhsa [17]

Answer:

2.6i

Step-by-step explanation:

undo the - by making it:  √-6.76= √6.76 x  √-1

then,  √-1 would be converted to imaginary number -> i

now rewrite it as  √6.76 x i or i√6.76 which is the same as the squareroot of 6.76 which is 2.6 times i.

Then just write your final answer as 2.6i

5 0
3 years ago
Read 2 more answers
Use linear approximation to estimate f (2.85 )given that f (3 )equals 2 and f prime (3 )equals 5.
Allisa [31]

Answer:

Step-by-step explanation:

Given that,

f(3) = 2

f'(3) = 5.

We want to estimate f(2.85)

The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".

At x = a, y = f(a) and the slope of the tangent line is f'(a).

So, in point slope form, the tangent line has equation

y − f(a) = f'(a)(x − a)

The linearization solves for y by adding f(a) to both sides

f(x) = f(a) + f'(a)(x − a).

Given that,

f(3) = 2,

f'(3) = 5

a = 3, we want to find f(2.85)

x = 2.85

Therefore,

f(x) = f(a) + f'(a)(x − a)

f(2.85) = 2 + 5(2.85 - 3)

f(2.85) = 2 + 5×-0.15

f(2.85) = 2 - 0.75

f(2.85) = 1.25

5 0
3 years ago
2 - ( - 4.51) = _____________
murzikaleks [220]
Your answer is, 6.51.

6 0
3 years ago
Read 2 more answers
Solve 3x^2 + 4x - 12 = 0
Andrei [34K]

Answer: x^2 = 2

Step-by-step explanation: 3x^2 + 4x=12

                                             6x^2=12

                                             x^2= 12/6

                                             x^2= 2

4 0
3 years ago
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