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nekit [7.7K]
2 years ago
10

Find area of the shaded portion of the figure ​

Mathematics
1 answer:
Nikitich [7]2 years ago
4 0

Answer:

\sf C) \quad 57 \frac34 \:cm^2

Step-by-step explanation:

To find the shaded area, subtract the area of the semicircle from the area of the rectangle.

<u>Formulae</u>

\textsf{Area of a rectangle}=\textsf{width} \times \textsf{length}

\textsf{Area of a semicircle}=\dfrac12 \pi r^2 \quad \textsf{(where r is the radius)}

\textsf{Diameter of a circle}=2r \quad \textsf{(where r is the radius)}

<u>Area of rectangle</u>

Given dimensions of the rectangle:

  • width = 7 cm
  • length = 11 cm

Substituting these values into the formula:

\implies \textsf{Area}=\textsf{7} \times \textsf{11}=77\: \sf cm^2

<u>Area of semicircle</u>

Diameter of semicircle = 11 - 2 - 2 = 7 cm

⇒ Radius (r) = 7 ÷ 2 = 3.5 cm

\textsf{let}\: \pi=\dfrac{22}{7}

\implies \textsf{Area}=\dfrac12 \left(\dfrac{22}{7}\right) (3.5)^2=19.25\: \sf cm^2

<u>Area of shaded region</u>

= area of rectangle - area of semicircle

= 77 - 19.25

= 57.75

\sf =57 \frac34 \:cm^2

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Answer:

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we know that for any general equation of the parabola of the type y=ax^{2} +b x+c the vertex of the parabola is given by (h,k)

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so focus is (-2,\frac{1}{4} )

now the directrix of the parabola is y=\frac{-1}{4}.




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