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LekaFEV [45]
3 years ago
9

The probability of a middle school student owning a skateboard is 0.58, of owning a bicycle is 0.48 and of owning both is 0.45.

If a middle school student is chosen at random, what is the probability that the middle school student owns a skateboard or a bicycle?
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0

Answer:

The probability that the middle school student owns a skateboard or a bicycle is 0.61.

Step-by-step explanation:

We are given that the probability of a middle school student owning a skateboard is 0.58, of owning a bicycle is 0.48, and owning both is 0.45.

A middle school student is chosen at random.

Let the probability of student owning a skateboard = P(S) = 0.58

The probability of student owning a bicycle = P(B) = 0.48

The probability of student owning both = P(S \bigcap B) = 0.45

Now, the probability that the middle school student owns a skateboard or a bicycle is given by = P(S \bigcup B)

        P(S \bigcup B) = P(S) + P(B) - P(S \bigcap B)

                      = 0.58 + 0.48 - 0.45

                      = 0.61

Hence, the probability that the middle school student owns a skateboard or a bicycle is 0.61.

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Step-by-step explanation:

Given the following functions

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Substitutw 3 into 1

From 1:

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(1/4)^(64+y+y) = 256

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The top of the Boulder Dam has an angle of elevation of 1.2 radians from a point on the Colorado River. Measuring the angle of e
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Step-by-step explanation:

The solution diagram is attached below :

Converting radian measurement to degree :

radian angle * 180/π = degree angle

1.2 * 180/π = 68.755°

0.9 * 180/π = 51.566°

Height of dam is h:

Using trigonometry :

Tan θ = opposite / Adjacent

Tan 68.755° = h / x

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Tan 51.566° = h / (155+x)

h = (155+x) tan 51.566° - - - (2)

Equate (1) and (2)

x Tan 68.755 = (155+x) Tan 51.566

x Tan 68.755 = 155tan 51.566 + x tan 51.566

x Tan 68.755 = 195.32311 + x Tan 51.566

x Tan 68.755 - x Tan 51.566 = 195.32311

x(tan 68.755 - tan 51.566) = 195.32311

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Answer:

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3 years ago
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