Answer:
Well first you would do (12.4-315) then you would -315 and you would get
Step-by-step explanation:
12.4-315=-302.6- -315
But the -315 becomes positive 315 because the minus and neg symbols rule each other out. So the next part would be -302.6-315= -617.6


Let
be the unknown number.
As per the question, we have

➺
➺
➺
➺
➺
Therefore,
should be subtracted from the product of
and
to get
.


➼
➼
➼
➼
➼


Answer:
9a^3b^3.
Step-by-step explanation:
The GCF of 9 and 27 is 9.
For a^4 and a^3 it is a^3.
For b^4 and b^3 it is b^3.
Answer is therefore:
9a^3b^3.
<u>ANSWER:
</u>
The value of x after evaluating the given equation x + 6 - 5 = 8 - 2 is 5.
<u>SOLUTION:
</u>
Given, equation in one variable is x + 6 – 5 = 8 – 2
And, now, we have to find the value of the variable x in the equation by solving the given equation.
So, let us solve the given equation for x.
Then, x + 6 – 5 = 8 – 2
x = 8 – 2 – (6 – 5) [sending all the numerical terms on left side to the right side.
x = 8 – 2 – 6 + 5
x = 8 + 5 – 2 – 6
x = 13 – 8 = 5
Hence, the value of x after evaluating the given equation is 5.
Answer:
The length of side BC is 2.8 units
Step-by-step explanation:
* Lets revise how to find the distance between two points
- If there are two points their coordinates are (x1 , y1) and (x2 , y2),
then we can find the distance between them by this rule:
d = √[(x2 - x1)² + (y2 - y1)²]
- Now lets solve the problem
∵ B = (3 , 3)
∵ C = (5 , 1)
- To find the length of BC use the rule of the distance above
- Let point B is (x1 , y1) and point C is (x2 , y2)
∵ x1 = 3 and x2 = 5
∵ y1 = 3 and y2 = 1
∴ BC = √[(5 - 3)² + (1 - 3)²]
∴ BC = √[(2)² + (-2)²]
∴ BC = √[4 + 4] = √8 = 2.8 units
* The length of side BC is 2.8 units